This is my final comment on this topic. Admitting points as squares makes these square covering problems uninteresting. By placing the point-squares on the boundary you can cover a square with an arbitrary number of them.
--- Frank C. Wimberly 140 Calle Ojo Feliz, Santa Fe, NM 87505 505 670-9918 Santa Fe, NM On Thu, Jul 23, 2020, 6:07 PM Jon Zingale <jonzing...@gmail.com> wrote: > Huh, that's fun. I love that my TI-86 correctly evaluates: > (10+6√3)^(1/3) + (10-6√3)^(1/3) to 2, just saying :) > > > > -- > Sent from: http://friam.471366.n2.nabble.com/ > > - .... . -..-. . -. -.. -..-. .. ... -..-. .... . .-. . > FRIAM Applied Complexity Group listserv > Zoom Fridays 9:30a-12p Mtn GMT-6 bit.ly/virtualfriam > un/subscribe http://redfish.com/mailman/listinfo/friam_redfish.com > archives: http://friam.471366.n2.nabble.com/ > FRIAM-COMIC <http://friam.471366.n2.nabble.com/FRIAM-COMIC> > http://friam-comic.blogspot.com/ >
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