Re: std::isfinite broken?

[Paolo Carlini]

Neal Becker wrote:
I found that compiling without -ffast-math would allow std::isfinite to
work.  Sorry if the statement was confusing.  The code looks something
like:
[calculate x]
if (not isfinite (x))
  throw std::runtime_error ("blah")
  
Well, -ffast-math implies -ffinite-math-only, I think you have to pass 
-fno-finite-math-only if you want to deal correctly with infinities.

Paolo.