Gidi Nave <gidi.nav...@gmail.com> writes: > On Tue, Jan 11, 2011 at 5:34 PM, Ian Lance Taylor <i...@google.com> wrote: > >> So why doesn't d1 = d1 + -96 match the last instruction there? >> > because it's: add d,d unsigned > we don't have: add d,d signed > > and in this case we need: d = r + (-96)
(Please don't top-post on this mailing list. Thanks.) Addition of signed and unsigned numbers is the same operation at the machine level. Are there limitations on the signed value? If so, is there is a sub instruction? Ian
