> No, it would not. By statute, in the U.S., a derivative work is a That's not about software, and that's only one jurisdiction.
> Programs written to interoperate with other programs are not derivative > works of those programs. True, but we're not talking about that. The example you're replying to was a scheduler which is an intimate part of a kernel, definitely not a separate program that interacts with the kernel. -- Ciarán O'Riordan, +32 477 36 44 19, http://ciaran.compsoc.com/ Support free software, join FSFE's Fellowship: http://fsfe.org Recent blog entries: http://fsfe.org/fellows/ciaran/ciaran_s_free_software_notes/links_gnu_osm_gnewsense_bangalore http://fsfe.org/fellows/ciaran/ciaran_s_free_software_notes/japanese_pdfs_part_2_xetex http://fsfe.org/fellows/ciaran/ciaran_s_free_software_notes/links_translation_bsod_orwell_releases http://fsfe.org/fellows/ciaran/ciaran_s_free_software_notes/fsfe_meeting_tonight_in_brussels_thurs_7th _______________________________________________ gnu-misc-discuss mailing list [email protected] http://lists.gnu.org/mailman/listinfo/gnu-misc-discuss
