does this do what you're after? http://grasshopper3d.googlegroups.com/web/splinepoints.jpg?hl=en&gsc=VdKE9RYAAADaqfGAVwtgVTdj2HJNdqeXOkh0iBmraMEV23BitRBh_w
not elegant I'm afraid, there's probably a more efficient way, but I am little more than a mere noob myself On Mar 6, 3:06 pm, aseid <[email protected]> wrote: > I figured that however, how do I substitute the new z value into the > new list while keeping the same x and y at that indexed location on > the sampled line > > On Mar 6, 9:55 am, KCCaine <[email protected]> wrote: > > > > > You will only modify the line in this way if it was generated from the > > points, not vice versa. You need to make a new line from the modified > > points as your final step. > > > On Mar 6, 1:51 pm, aseid <[email protected]> wrote: > > > > This may seem very elementary but I am really just getting started > > > here: > > > > I want to extract a item from a list of data and then reinsert it into > > > another list of the exact same points except cull the point from the > > > previous line > > > > So its a extract and replace scenario > > > > I have created a spline and used the DIV component to divide it into > > > points. I list the points, and index the point i want to affect, then > > > i use the move compnent, a z vector and a slider to affect the height > > > but i get a copy of the point rather than a modification to the > > > spline. > > > > I can post the definition file if need be > > > > Any ideas?- Hide quoted text - > > - Show quoted text -
