*NO* LR R1,R1 will not zero out R1. SR R1,R1 will zero out R1.
<snip> Prior to the L R2,PARMJOBC, there is a LR R1,R1 which zeroes out R1 right? So, does R1 have data in it or an address? I was assuming that R1 had data in it (with leading zeroes and 8 on the end) and I'm trying to add other values to that value. How can I do that if not the way I tried (ICM followed by the MVC and A)? </snip> <<SNIP>> A mask of 7 loads the low order 3 bytes, so that r1 would contain whatever the high order byte it contained originally plus 000008 in the low order 3 bytes. L R2,PARMJOBC ICM R1,7,0(R2) If smf30cps contains 00000001, then the first 4 bytes of wk1 would contain 00000001 after the move And r1 would also contain 00000001 after the add, assuming WK1 is on a full word boundary. MVC WK1(4),SMF30CPS A R1,WK1 <</SNIP>> <SNIP> In our IEFACTRT (accounting exit), an assembler program, it has the following commands: L R2,PARMJOBC ICM R1,7,0(R2) If PARMJOBC contains a binary integer length of 4 with 00 00 00 08, what ends up in all bits of R1? I am trying to add additional values to what is in R1 by doing: MVC WK1(4),SMF30CPS A R1,WK1 </SNIP> ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to lists...@bama.ua.edu with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html
