Noting both DSI* and AOF* messages in the logs, have you considered "Log Analysis Program"? https://www.ibm.com/docs/en/z-netview/6.2.1?topic=tuning-log-analysis-program
On Tue, Jan 4, 2022 at 2:49 AM Jason Cai <ibmm...@foxmail.com> wrote: > Hello Kolusu > > Due to the holiday, I have only studied the sample JCL you provided in > the past few days. > > The JCL is of great help to me. Thanks for your help! > > I failed to describe our needs clearly last time. > > We hope to use dfsort to compare today’s operlog with yesterday’s. > > There are two kinds of messages in operlog. > 1. single-line message > 2. multi-line message > > The problem is that the number of lines in a multi-line message is > variable. > > To simplify the problem, we make two operlog. operlog is FBM and LRECL=133 > > How is a duplicate identified? > > The 'key' is the position from 58 to 133. > > The duplicate is identified by the 'key' > > > Below is operlog(1) . There are 6 messages in the operlog > > operlog(1): > > 1 20 > 58 > 133 > > ----------------------------+------------------------------------------------------+-------------------------.................-------+ > M 4040000 CUK1 18179 16:02:44.45 STC00280 00000090 HZS0002E A1 > E > B1 > M 4040000 CUK1 18179 16:03:44.45 STC00280 00000090 HZS0002E A1 > E > B1 > MR0000000 CUK1 18179 16:08:04.53 AWRK08 00000090 $HASP636 A2A2 > DR > B2B2 > DR > C2C2 > ER > D2D2 > MR0000000 CUK1 18179 16:08:05.53 AWRK08 00000090 $HASP636 A2A2 > DR > B2B2 > DR > C2C2 > ER > D2D2 > N 4008000 CUK1 18179 16:08:06.12 STC00389 00000090 AOF869I > A3A3A3 > N 8000000 CUK1 18179 16:33:58.48 00000090 DSI064A > A4A4A4A4 > S > B4B4B4B4 > > --------------------------------------------------------------------------------------------------------------------------------------------- > Question1 : > > Because the number of lines in a multi-line message is variable, Could > you help us to get the following result (operlog(2)) by > > selecting the first duplicate of multi-line messages or single-line > messages ? > > operlog(2): > > 1 20 > 58 > 133 > > ----------------------------+------------------------------------------------------+-------------------------.................-------+ > M 4040000 CUK1 18179 16:02:44.45 STC00280 00000090 HZS0002E A1 > E > B1 > MR0000000 CUK1 18179 16:08:04.53 AWRK08 00000090 $HASP636 A2A2 > DR > B2B2 > DR > C2C2 > ER > D2D2 > N 4008000 CUK1 18179 16:08:06.12 STC00389 00000090 AOF869I > A3A3A3 > N 8000000 CUK1 18179 16:33:58.48 00000090 DSI064A > A4A4A4A4 > S > B4B4B4B4 > S > C4C4C4C4 > > --------------------------------------------------------------------------------------------------------------------------------------------- > > Now there are 4 messages in operlog(2) > > > Now we made the other operlog(3). please see it below . There are two > messages in the operlog(3) > > operlog(3): > > 1 20 > 58 > 133 > > ----------------------------+------------------------------------------------------+-------------------------.................-------+ > M 4040000 CUK1 18179 16:02:44.45 STC00280 00000090 HZS0002E A1 > E > B1 > MR0000000 CUK1 18179 16:08:04.53 AWRK08 00000090 $HASP636 A2A2 > DR > B2B2 > DR > C2C2 > ER > D2D2 > > --------------------------------------------------------------------------------------------------------------------------------------------- > > Question 2 : > > Because the number of lines in a multi-line message is variable,could you > help us to compare the operlog(2) with the operlog(3) to get the operlog(4) > > The compare's 'key' is also the position from 58 to 133. > > > > > operlog(4): > > 1 20 > 58 > 133 > > ----------------------------+------------------------------------------------------+-------------------------.................-------+ > N 4008000 CUK1 18179 16:08:06.12 STC00389 00000090 AOF869I > A3A3A3 > N 8000000 CUK1 18179 16:33:58.48 00000090 DSI064A > A4A4A4A4 > S > B4B4B4B4 > S > C4C4C4C4 > > --------------------------------------------------------------------------------------------------------------------------------------------- > > > Question3: > > If the number of lines in a multi-line message is fixed, the manual tells > us how to merge multiple lines into > a single line? > > Because the number of lines in a multi-line message is actually variable, > Could you help us to use ICETOOL operator RESIZE to merge multiple lines > into > a single line for operlog(2) and operlog(3). > > After merging multiple lines into a single line for operlog(2) and > operlog(3), we could compare them. > > Question4 : > > After comparing them , how to split a single line into multiple lines? > > > > Thanks a lot! > > Jason Cai > > ---------------------------------------------------------------------- > For IBM-MAIN subscribe / signoff / archive access instructions, > send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN > ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN
