On 26/07/2013 8:36 AM, Bernd Oppolzer wrote:
I guess that LANGLVL(LONGLONG) is already in effect,
because LANGLVL(LONGLONG) is implicitly set with LANGLVL(EXTENDED);
if not, the compiler would not accept the long long declarations, I
guess,
and it handles the long long variables in the beginning of the function
as 64 bit values (see the SRAG).
I agree. I couldn't see a LANGLVL(LONGLONG). I compile using
LANGLVL(EXTENDED0X) and LONGLONG is not the default.
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