Sorry, but I deleted the email which had the original question. Just for "fun" (but no profit), I wrote the following C code to display the name of the job under which the program is running. It can be improved a bit, but it shows the basics.
#include <stdlib.h> #include <stdio.h> #include <string.h> int main(int argc, char *argv[]) { char *psaaold; char *ascbjbni; char *ascbjbns; char *ascbjbn; char jobname[9]; psaaold=*(char **)0x224; /* address of PSAAOLD */ //printf("%s\n",psaaold); ascbjbni=*(char **)(psaaold+0xac); ascbjbns=*(char **)(psaaold+0xb0); ascbjbn =ascbjbni; //printf("%s\n",ascbjbni); if (ascbjbn == NULL) ascbjbn=ascbjbns; memcpy(jobname,ascbjbn,8); *(jobname+8)='\0'; printf("%s - %8.8s\n",jobname,ascbjbn); } -- I have a theory that it's impossible to prove anything, but I can't prove it. Maranatha! <>< John McKown ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN