Yes, CTC must be an even/odd pair. On Fri, Jul 11, 2008 at 2:30 PM, McKown, John <[EMAIL PROTECTED]> wrote:
> Doesn't a CTC connection require the even/odd address for send/receive? > > > -- > John McKown > Senior Systems Programmer > HealthMarkets > Keeping the Promise of Affordable Coverage > Administrative Services Group > Information Technology > > This message (including any attachments) contains confidential information > intended for a specific individual and purpose, and its content is protected > by law. If you are not the intended recipient, you should delete this > message and are hereby notified that any disclosure, copying, or > distribution of this transmission, or taking any action based on it, is > strictly prohibited. > > > > ------------------------------ > *From:* The IBM z/VM Operating System [mailto:[EMAIL PROTECTED] *On > Behalf Of *Mark Pace > *Sent:* Friday, July 11, 2008 1:29 PM > *To:* IBMVM@LISTSERV.UARK.EDU > *Subject:* Re: HiperSockets > > Hmm - Thought you could do that, as long as you used virtual addresses and > the 1st address was even. Maybe I'm confused with another OS. I work on to > many. > > [snip] > > > > -- > Mark Pace > Mainline Information Systems > > -- Mark Pace Mainline Information Systems
