I'm sorry, but I don't quite understand your code.
On Oct 20, 5:16 pm, Andrea Giammarchi <andrea.giammar...@gmail.com>
wrote:
> On Tue, Oct 20, 2009 at 5:06 AM, gMinuses <gminu...@gmail.com> wrote:
>
> > Like I said: setting data property in ajaxSetup won't work, if it's
> > specified
> > in individual ajax calls.
>
> if it's specified in individual ajax calls you don't need defaults then,
> otherwise append data in the url or set the data extending original one.
>
> // custom method
> jQuery.ajaxSettings.ext = (function(anonymous){
> return function ext(o){
> anonymous.prototype = this.data || {};
> var k, result = new anonymous;
> if(o){
> for(k in o)
> result[k] = o[k]
> ;
> };
> return result;
> };
>
> })(Function());
>
> // your defaults
> jQuery.ajaxSetup({
> data:{
> defaultKey:"defaultValue",
> otherKey:"otherValue"
> }
>
> });
>
> console.log(jQuery.ajaxSettings.ext({test:123}));
>
> Regards
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"jQuery Development" group.
To post to this group, send email to jquery-dev@googlegroups.com
To unsubscribe from this group, send email to
jquery-dev+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/jquery-dev?hl=en
-~----------~----~----~----~------~----~------~--~---