If someone wants to pass in a random object to be extended we won't
stop them. So yeah, someone could do:
jQuery.extend([1,2], [3]) and get [3,2] as a result - not sure why you
would want to, though. I can't think of a reason to explicitly prevent
this behavior, at least.
(On a related note I've renamed isObject to isObjectLiteral.)
--John
On Tue, Nov 10, 2009 at 9:10 PM, Robert Katić <robert.ka...@gmail.com> wrote:
> Wat a hell is going here?
>
> // Recurse if we're merging object values
> if ( deep && copy && typeof copy === "object" && !copy.nodeType ) {
> var clone;
>
> if ( src ) {
> clone = src;
> } else if ( jQuery.isArray(copy) ) {
> clone = [];
> } else if ( jQuery.isObject(copy) ) {
> clone = {};
> } else {
> clone = copy;
> }
>
> // Never move original objects, clone them
> target[ name ] = jQuery.extend( deep, clone, copy );
>
>
> You are going to extend with any object including a Date, a String, a
> Number... (ah yes, excluding nodes).
>
> You are going to extend (with) arrays? [1,2] and [4] to obtain [4,2].
> Really?
>
> If an object is not an array nor an object literal then extend object
> with itself???
>
> The only things to extend recursively are objects literals to me:
>
> if ( deep && copy && jQuery.isObject(copy) && (!src || jQuery.isObject
> (src)) ) {
> target[ name ] = jQuery.extend( deep, src || {}, copy );
> }
>
> Am I loosing my mind? :)
>
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