Ah yes, I see your point now. It looks like this may have gotten munged in the overhaul done by Yehuda.
If you want to make a patch with some good test cases I'll happily land it. --John On Wed, Nov 11, 2009 at 3:27 AM, Robert Katić <robert.ka...@gmail.com> wrote: > Ah, yes, since options.nodes was already defined before extending, it > will not become jQuery("#content") (with all jQuery methods copied > inside itself), but something between jQuery("div") and jQuery > ("#content") (with all jQuery methods copied inside itself). Even > worse. > > I have to suppose that the author was drunk when he was writing it. :) > > Am I missing something? > > On Nov 11, 8:16 am, Robert Katić <robert.ka...@gmail.com> wrote: >> I don't get your point. I am talking about what is extended >> recursively, not what is passed as argument. >> >> If you have something like this: >> >> var options = { >> nodes: jQuery("div"), >> num: 4, >> date: new Date >> >> }; >> >> jQuery.extend(true, options, { >> nodes: jQuery("#content"), >> num: new Number(5), >> date: new Date >> >> }); >> >> then options.node would be the same jQuery("#content") object but now >> with all jQuery methods copied inside itself, options.num will remain >> 4, options.date remain unchanged. >> >> I think this behavior is not what someone would expect (I hope). >> >> On Nov 11, 5:09 am, John Resig <jere...@gmail.com> wrote: >> >> > If someone wants to pass in a random object to be extended we won't >> > stop them. So yeah, someone could do: >> >> > jQuery.extend([1,2], [3]) and get [3,2] as a result - not sure why you >> > would want to, though. I can't think of a reason to explicitly prevent >> > this behavior, at least. >> >> > (On a related note I've renamed isObject to isObjectLiteral.) >> >> > --John >> >> > On Tue, Nov 10, 2009 at 9:10 PM, Robert Katić <robert.ka...@gmail.com> >> > wrote: >> > > Wat a hell is going here? >> >> > > // Recurse if we're merging object values >> > > if ( deep && copy && typeof copy === "object" && !copy.nodeType ) { >> > > var clone; >> >> > > if ( src ) { >> > > clone = src; >> > > } else if ( jQuery.isArray(copy) ) { >> > > clone = []; >> > > } else if ( jQuery.isObject(copy) ) { >> > > clone = {}; >> > > } else { >> > > clone = copy; >> > > } >> >> > > // Never move original objects, clone them >> > > target[ name ] = jQuery.extend( deep, clone, copy ); >> >> > > You are going to extend with any object including a Date, a String, a >> > > Number... (ah yes, excluding nodes). >> >> > > You are going to extend (with) arrays? [1,2] and [4] to obtain [4,2]. >> > > Really? >> >> > > If an object is not an array nor an object literal then extend object >> > > with itself??? >> >> > > The only things to extend recursively are objects literals to me: >> >> > > if ( deep && copy && jQuery.isObject(copy) && (!src || jQuery.isObject >> > > (src)) ) { >> > > target[ name ] = jQuery.extend( deep, src || {}, copy ); >> > > } >> >> > > Am I loosing my mind? :) >> >> > > -- >> >> > > You received this message because you are subscribed to the Google >> > > Groups "jQuery Development" group. >> > > To post to this group, send email to jquery-...@googlegroups.com. >> > > To unsubscribe from this group, send email to >> > > jquery-dev+unsubscr...@googlegroups.com. >> > > For more options, visit this group >> > > athttp://groups.google.com/group/jquery-dev?hl=. > > -- > > You received this message because you are subscribed to the Google Groups > "jQuery Development" group. > To post to this group, send email to jquery-...@googlegroups.com. > To unsubscribe from this group, send email to > jquery-dev+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/jquery-dev?hl=. > > > -- You received this message because you are subscribed to the Google Groups "jQuery Development" group. To post to this group, send email to jquery-...@googlegroups.com. To unsubscribe from this group, send email to jquery-dev+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/jquery-dev?hl=.