http://dev.jquery.com/ticket/5494

I am sorry if I had hurt someone, it wasn't in my intention. That
munged code was there a quite long time, and during reporting it, my
mood was going a little worse.

On Nov 11, 3:22 pm, John Resig <jere...@gmail.com> wrote:
> Ah yes, I see your point now. It looks like this may have gotten
> munged in the overhaul done by Yehuda.
>
> If you want to make a patch with some good test cases I'll happily land it.
>
> --John
>
> On Wed, Nov 11, 2009 at 3:27 AM, Robert Katić <robert.ka...@gmail.com> wrote:
> > Ah, yes, since options.nodes was already defined before extending, it
> > will not become jQuery("#content") (with all jQuery methods copied
> > inside itself), but something between jQuery("div") and jQuery
> > ("#content") (with all jQuery methods copied inside itself). Even
> > worse.
>
> > I have to suppose that the author was drunk when he was writing it. :)
>
> > Am I missing something?
>
> > On Nov 11, 8:16 am, Robert Katić <robert.ka...@gmail.com> wrote:
> >> I don't get your point. I am talking about what is extended
> >> recursively, not what is passed as argument.
>
> >> If you have something like this:
>
> >> var options = {
> >>   nodes: jQuery("div"),
> >>   num: 4,
> >>   date: new Date
>
> >> };
>
> >> jQuery.extend(true, options, {
> >>  nodes: jQuery("#content"),
> >>  num: new Number(5),
> >>  date: new Date
>
> >> });
>
> >> then options.node would be the same jQuery("#content") object but now
> >> with all jQuery methods copied inside itself, options.num will remain
> >> 4, options.date remain unchanged.
>
> >> I think this behavior is not what someone would expect (I hope).
>
> >> On Nov 11, 5:09 am, John Resig <jere...@gmail.com> wrote:
>
> >> > If someone wants to pass in a random object to be extended we won't
> >> > stop them. So yeah, someone could do:
>
> >> > jQuery.extend([1,2], [3]) and get [3,2] as a result - not sure why you
> >> > would want to, though. I can't think of a reason to explicitly prevent
> >> > this behavior, at least.
>
> >> > (On a related note I've renamed isObject to isObjectLiteral.)
>
> >> > --John
>
> >> > On Tue, Nov 10, 2009 at 9:10 PM, Robert Katić <robert.ka...@gmail.com> 
> >> > wrote:
> >> > > Wat a hell is going here?
>
> >> > >  // Recurse if we're merging object values
> >> > > if ( deep && copy && typeof copy === "object" && !copy.nodeType ) {
> >> > >  var clone;
>
> >> > >  if ( src ) {
> >> > >    clone = src;
> >> > >  } else if ( jQuery.isArray(copy) ) {
> >> > >    clone = [];
> >> > >  } else if ( jQuery.isObject(copy) ) {
> >> > >    clone = {};
> >> > >  } else {
> >> > >    clone = copy;
> >> > >  }
>
> >> > >  // Never move original objects, clone them
> >> > >  target[ name ] = jQuery.extend( deep, clone, copy );
>
> >> > > You are going to extend with any object including a Date, a String, a
> >> > > Number... (ah yes, excluding nodes).
>
> >> > > You are going to extend (with) arrays? [1,2] and [4] to obtain [4,2].
> >> > > Really?
>
> >> > > If an object is not an array nor an object literal then extend object
> >> > > with itself???
>
> >> > > The only things to extend recursively are objects literals to me:
>
> >> > > if ( deep && copy && jQuery.isObject(copy) && (!src || jQuery.isObject
> >> > > (src)) ) {
> >> > >  target[ name ] = jQuery.extend( deep, src || {}, copy );
> >> > > }
>
> >> > > Am I loosing my mind? :)
>
> >> > > --
>
> >> > > You received this message because you are subscribed to the Google 
> >> > > Groups "jQuery Development" group.
> >> > > To post to this group, send email to jquery-...@googlegroups.com.
> >> > > To unsubscribe from this group, send email to 
> >> > > jquery-dev+unsubscr...@googlegroups.com.
> >> > > For more options, visit this group 
> >> > > athttp://groups.google.com/group/jquery-dev?hl=.
>
> > --
>
> > You received this message because you are subscribed to the Google Groups 
> > "jQuery Development" group.
> > To post to this group, send email to jquery-...@googlegroups.com.
> > To unsubscribe from this group, send email to 
> > jquery-dev+unsubscr...@googlegroups.com.
> > For more options, visit this group 
> > athttp://groups.google.com/group/jquery-dev?hl=.

--

You received this message because you are subscribed to the Google Groups 
"jQuery Development" group.
To post to this group, send email to jquery-...@googlegroups.com.
To unsubscribe from this group, send email to 
jquery-dev+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/jquery-dev?hl=.


Reply via email to