Tom,
You're confusing ajaxForm and ajaxSubmit. When you use ajaxForm you do not
need to also use ajaxSubmit. ajaxForm will wire up the form and invoke
ajaxSubmit for you. If you set breakpoints you'll notice that your form is
actually being submitted twice. You can simplify the code to this:
$('#button').ajaxForm({
url: 'tom_backend.php',
success: function() {
alert('Ajax call complete.')
}
});
Or if you change the action in your markup to 'tom_backend.php' (instead of
'/gg/tom_backend.php') then you could just do this:
$('#button').ajaxForm(function() {
alert('Ajax call complete.')
});
Mike
On 9/19/07, Tom <[EMAIL PROTECTED]> wrote:
>
>
> Hi Mike
>
> I have throw the files up here
>
> http://www.zendurl.com/tommydiy/tom.html
>
> The JS files can be viewed at
> http://www.zendurl.com/tommydiy/jquery.form.js
> http://www.zendurl.com/tommydiy/jquery.js
> http://www.zendurl.com/tommydiy/tom.js
>
> and tom_backend.php is displayed below
>
> <?php
>
> // variables are passed as GET paramerters
> $action=$_POST['action'];
>
> // action buttons
> if ($action==2)
> {
> if ($action==2)
> {
> $type='soft';
> echo "Sending $type reset command... ";
> }
> }
> ?>
>
> PS I do not call all files 'tom' normally Its not an ego thing :p We
> do not have a dedicated external sever in here.
>
> Any insight much appreciated.
> T
>
> On Sep 19, 12:55 pm, "Mike Alsup" <[EMAIL PROTECTED]> wrote:
> > Tom,
> >
> > Do you have a page the demonstrates this problem?
> >
> > Mike
> >
> > On 9/19/07, TommyDIY <[EMAIL PROTECTED]> wrote:
> >
> >
> >
> > > Hi
> >
> > > I am just starting to use jquery so have downloaded the latest
> > > jquery.js version (v 1.2.1). I wanted to utilise form submission so
> > > also grabbed the jquery.form.js
> >
> > > However it throws an error on line 209 jquery.form.js
> > > "options.url.indexOf is not a function"
> >
> > > Can anyone help me to get this working please?
> >
> > > Cheers
> > > Tom
>
>
