Thanks for setting me straight on that Mike.
Not that I have my example up and running I can play around with it
and try to learn something about jQuery. (Defo need to delve into some
tutorials on it)
Thanks for you prompt reply
Tom
On Sep 19, 2:10 pm, "Mike Alsup" <[EMAIL PROTECTED]> wrote:
> Tom,
>
> You're confusing ajaxForm and ajaxSubmit. When you use ajaxForm you do not
> need to also use ajaxSubmit. ajaxForm will wire up the form and invoke
> ajaxSubmit for you. If you set breakpoints you'll notice that your form is
> actually being submitted twice. You can simplify the code to this:
>
> $('#button').ajaxForm({
> url: 'tom_backend.php',
> success: function() {
> alert('Ajax call complete.')
> }
>
> });
>
> Or if you change the action in your markup to 'tom_backend.php' (instead of
> '/gg/tom_backend.php') then you could just do this:
>
> $('#button').ajaxForm(function() {
> alert('Ajax call complete.')
>
> });
>
> Mike
>
> On 9/19/07, Tom <[EMAIL PROTECTED]> wrote:
>
>
>
> > Hi Mike
>
> > I have throw the files up here
>
> >http://www.zendurl.com/tommydiy/tom.html
>
> > The JS files can be viewed at
> >http://www.zendurl.com/tommydiy/jquery.form.js
> >http://www.zendurl.com/tommydiy/jquery.js
> >http://www.zendurl.com/tommydiy/tom.js
>
> > and tom_backend.php is displayed below
>
> > <?php
>
> > // variables are passed as GET paramerters
> > $action=$_POST['action'];
>
> > // action buttons
> > if ($action==2)
> > {
> > if ($action==2)
> > {
> > $type='soft';
> > echo "Sending $type reset command... ";
> > }
> > }
> > ?>
>
> > PS I do not call all files 'tom' normally Its not an ego thing :p We
> > do not have a dedicated external sever in here.
>
> > Any insight much appreciated.
> > T
>
> > On Sep 19, 12:55 pm, "Mike Alsup" <[EMAIL PROTECTED]> wrote:
> > > Tom,
>
> > > Do you have a page the demonstrates this problem?
>
> > > Mike
>
> > > On 9/19/07, TommyDIY <[EMAIL PROTECTED]> wrote:
>
> > > > Hi
>
> > > > I am just starting to use jquery so have downloaded the latest
> > > > jquery.js version (v 1.2.1). I wanted to utilise form submission so
> > > > also grabbed the jquery.form.js
>
> > > > However it throws an error on line 209 jquery.form.js
> > > > "options.url.indexOf is not a function"
>
> > > > Can anyone help me to get this working please?
>
> > > > Cheers
> > > > Tom
