Ok, I updated it. I made it Very jQuery.
$("input[type=checkbox]").click(function(){
divClass = $(this).attr("class");
if ($(this).is(":checked")) {
$("#" + divClass).show();
}
else if($(this).not(":checked")) {
$("#" + divClass).hide();
}
});
I refactored it three times. I kept thinking, "hmm, I think this should be
shorter".
I think there is probably a way to make it even shorter with Toggle.
Anyone?
Glen
On Dec 6, 2007 8:22 PM, Glen Lipka <[EMAIL PROTECTED]> wrote:
> Ahh, I think I get it.
>
> Input 1 and 2 both are controlling the first div.
> Input 3 controls div 2
> input 4 controls div 3
> input 5 controls div 4
>
> Yes? I can modify the demo.
>
> Glen
>
>
> On Dec 6, 2007 2:46 PM, Ryan <[EMAIL PROTECTED]> wrote:
>
> >
> > This part works:
> > Select X, get Div 1
> > or
> > Select Y, get Div 1
> > or
> > Select X and Y, get Div1
> >
> > This part doesn't:
> > When X and Y are selected, Div1 is showing
> > If X is unselected and Y remains selected, Div1 is still showing
> >
> > Basically, if X and Y are selected and then X is unselected, I want
> > Div1 to remain showing because Select Y, get Div1 still holds true.
> > This is where I'm having a problem. When X is unselected, it hides
> > Div1. Make sense?
> >
> >
> >
> > On Dec 6, 3:37 pm, "Glen Lipka" <[EMAIL PROTECTED]> wrote:
> > > I dont get it. :)
> > >
> > > Say it again as a use case:
> > > 1. click on X
> > > 2. expect results: div Y does something.
> > >
> > > Glen
> > >
> > > On Dec 6, 2007 11:22 AM, Ryan < [EMAIL PROTECTED]> wrote:
> > >
> > >
> > >
> > > > Actually, what I need it to do is show one instance of Div 4, not
> > > > two. I'm using the div for a text field, so I only need to show one
> >
> > > > version of it. The checkboxes showing the div are independent of
> > each
> > > > other in value, but have the same corresponding text field which
> > > > should be filled out if either or both of these checkboxes are
> > > > selected. Does that make sense?
> > >
> > > > On Dec 6, 12:36 pm, "Glen Lipka" <[EMAIL PROTECTED]> wrote:
> > > > > I whipped a demo. Does this do what you
> > > > want?http://www.commadot.com/jquery/checkBoxShow.php
> > >
> > > > > Couple of tips:
> > >
> > > > > 1. Try to avoid putting onclick handlers in your html. jQuery
> > does
> > > > > this really easily and makes your html easier to read.
> > > > > 2. getElementByID can be expressed as
> > $("#yourID").dosomething...
> > > > > Much more concise and jQuery-ish. :)
> > > > > 3. The toggle function will automatically show if hidden and
> > hide if
> > > > > shown without the IF shatement.
> > >
> > > > > Hope these help. When I first started jQuery, I had to forget
> > > > everything I
> > > > > knew about JS (which wasn't much). It just did it all without the
> > muss.
> > >
> > > > > Glen
> > >
> > > > > On Dec 6, 2007 8:30 AM, Ryan <[EMAIL PROTECTED]> wrote:
> > >
> > > > > > I'm completely versed in the show/hide options available, but
> > have a
> > > > > > problem I haven't been able to figure out. I'm hoping jquery
> > will have
> > > > > > the answer. I have 5 checkbox input options, the first two
> > options
> > > > > > providing the same show div. For example,
> > >
> > > > > > <html>
> > >
> > > > > > <head>
> > > > > > <script type="text/javascript">
> > > > > > <!--
> > > > > > function showMe (it, box) {
> > > > > > var vis = (box.checked) ? "block" : "none";
> > > > > > document.getElementById(it).style.display = vis;
> > > > > > }
> > > > > > //-->
> > > > > > </script>
> > > > > > </head>
> > >
> > > > > > <body>
> > >
> > > > > > <form>
> > > > > > <input type="checkbox" name="modtype" value="value1"
> > > > > > onclick="showMe('div1', this)" />value1
> > >
> > > > > > <input type="checkbox" name="modtype" value="value2"
> > > > > > onclick="showMe('div1', this)" />value2
> > >
> > > > > > <input type="checkbox" name="modtype" value="value3"
> > > > > > onclick="showMe('div2', this)" />value3
> > >
> > > > > > <input type="checkbox" name="modtype" value="value4"
> > > > > > onclick="showMe('div3', this)" />value4
> > >
> > > > > > <input type="checkbox" name="modtype" value="value5"
> > > > > > onclick="showMe('div4', this)" />value5
> > >
> > > > > > <div class="row" id="div1" style="display:none">Show Div 1</div>
> > > > > > <div class="row" id="div2" style="display:none">Show Div 2</div>
> >
> > > > > > <div class="row" id="div3" style="display:none">Show Div 3</div>
> > > > > > <div class="row" id="div4" style="display:none">Show Div 4</div>
> >
> > > > > > </form>
> > >
> > > > > > </body>
> > >
> > > > > > </html>
> > >
> > > > > > As you can see, the first two options should show the same div.
> > > > > > Selecting one or both isn't a problem, the div appears as
> > should, but
> > > > > > when deselecting one of the checkboxes, the div disappears even
> > though
> > > > > > one of the checkboxes is still selected.
> > >
> > > > > > Does anyone have an idea as to how I can get the div to remain
> > > > > > selected when one of the two checkboxes is deselected? Or, if
> > either
> > > > > > of the checkboxes are selected, to provide just one result?
> > >
> > > > > > Thanks!
> >
>
>
