Something like this?
var check1;
$("#ajax").ajaxForm({
success: function(data) {
check1 = data;
}
});
$("#target").ajaxSuccess(function(request, settings) {
if (check1 == "something") {
$(this).append(check1);
}
});
That's untested, but should work, so hopefully it's a starting point for
you.
- Richard
On Dec 14, 2007 3:23 PM, Mario Moura <[EMAIL PROTECTED]> wrote:
> Almost, the problem is always "check1 is not defined"
>
> Example:
>
> function checked(check) {
> this.check = check
> }
>
> $("#ajax").ajaxForm({
> success:
> function(data) {
> check1 = new checked(data)
> // do stuff with data;
> }
> });
>
> $("#target").ajaxSuccess(function(request, settings){
> $(function() {
> if (check1 == "something") {
> $(this).append(check1);
> }
> })
> });
>
> Ideas how can I fix "check1 is not defined"?
>
> Regards
>
> Mario Moura
>
> 2007/12/14, Mario Moura <[EMAIL PROTECTED]>:
>
> > Wow, thanks a lot Richard
> >
> > I can do this with php (quite simple) but I am lost with Jquery /
> > Javascript syntax. Could you help me?
> >
> > Example
> >
> > $("#mychild").ajaxForm({
> > success:
> > function(data) {
> > // do stuff with data;
> > function toCheck() {
> > $(data);
> > }
> > }
> > });
> >
> > // So for each Ajax request I will insert
> > function toCheck() {
> > $(data); // or I can get some data into $data like
> > $(data).attr("myid")
> > }
> >
> > // So I want check if toCheck() have a value or not but I will
> > let simple, just alert me.
> > // I dont know if the syntax is ok
> >
> > function pleaseAlertMe() {
> > alert(toCheck());
> > }
> >
> > I dont want (or I cant) pass the $(data) to a div and check
> > there by DOM I prefer check by function. If is it possible of course.
> >
> > And now I will study a lot of JavaScript Syntax. ;)
> >
> > Regards
> >
> > Mario Moura
> >
> > 2007/12/14, Richard D. Worth < [EMAIL PROTECTED]>:
> > >
> > > You could declare a function and give it a name, instead of using an
> > > anonymous function, then pass that as the success function for each ajax
> > > call.
> > >
> > > - Richard
> > >
> > > On Dec 14, 2007 8:51 AM, Mario Moura < [EMAIL PROTECTED]> wrote:
> > >
> > > > No.
> > > >
> > > > Let me explain better.
> > > >
> > > > In your scenario you made a individual AJAX request and into this
> > > > request you create rules.
> > > >
> > > > But JQuery could create an universal AjaxSucess to test all data
> > > > from all ajax requests.
> > > >
> > > > So imagine this scenario:
> > > >
> > > > The page have a lot of AJAX requests, something like ajaxform,
> > > > $.ajax, $.post, $.get
> > > >
> > > > So from response of each AJAX we could create a function like: (and
> > > > I will use switch)
> > > >
> > > >
> > > > $().ajaxSuccess (function() {
> > > > switch( $(data).attr("id") ) { // here I get the data from
> > > > AJAX Sucess every time happen could by by xml, json but I am using div
> > > > case 'myid':
> > > > // do stuff with data;
> > > > break;
> > > > case 'myid2':
> > > > // do stuff with data;
> > > > break;
> > > > }
> > > >
> > > > no matter if it is from $.ajax({"type": "POST", "url": " foo1.php",});
> > > > or $.ajax({"type": "POST", "url": "
> > > > foo2.php "}); or $.ajax({"type": "POST", "url": "foo3.php ",});
> > > >
> > > > But at this moment. I think is not possible. But could be a good
> > > > improve.
> > > >
> > > > Did you understand?
> > > >
> > > > Regards
> > > >
> > > > Mario Moura
> > > >
> > > > 2007/12/14, Giovanni Battista Lenoci < [EMAIL PROTECTED]>:
> > > >
> > > > >
> > > > > Don't know if I understood,
> > > > >
> > > > > $.ajax({"type": "POST",
> > > > > "url": " foo2.php",
> > > > > "data": data,
> > > > > "dataType": "json",
> > > > > "success": function(server_response) {
> > > > > switch(server_response.wich_function) {
> > > > > case '1':
> > > > > on_success_one(server_response);
> > > > > break;
> > > > > case '2':
> > > > > on_success_two(server_response);
> > > > > break;
> > > > > }
> > > > >
> > > > > });
> > > > >
> > > > >
> > > >
> > > >
> > > > --
> > > > Mário Alberto Chaves Moura
> > > > [EMAIL PROTECTED]
> > > > 31-3264-6203
> > > > 31-9157-6000
> > >
> > >
> > >
> >
> >
> > --
> > Mário Alberto Chaves Moura
> > [EMAIL PROTECTED]
> > 31-3264-6203
> > 31-9157-6000
> >
>
>
>
> --
> Mário Alberto Chaves Moura
> [EMAIL PROTECTED]
> 31-3264-6203
> 31-9157-6000
>
