What's "li" meant to be - in that code it's not assigned at all....
If it's meant to be "every list item on the page", then it should be
$("li"), and you'll also need to check whether or not the outer "ul" or
"ol" for the li is visible.
Liam
Aaron wrote:
well I don't plan using a class I am trying to use an id. in css I
have stuff declared like #image{css stuff here;}
here is the code I have.
$("#image").hover(
function(){
$(li).fadeIn("slow");
},
function(){
$(li).fadeOut("slow");
},
);
what I want to do is when the mouse goes over the image I want a
window not a popup window but a window that fades in on the right or
left of the image where it would have a list of other images and if
the mouse goes off the image and is not on that list area then it
would fade out.
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On May 3, 8:15 pm, Eddie <[EMAIL PROTECTED]> wrote:
Hi Aaron,
Try this:
$(".elementClass").hover(
function(){
$(this).fadeIn("normal");
},
function(){
$(this).fadeOut("normal");
},
);
If it's not what you expected, post your code.
On 3 maio, 17:50, Aaron <[EMAIL PROTECTED]> wrote:
Hi I am somewhat new here and to jquery I learned javascript and have
a previous knowledge of programming.
I am having trouble using the hover and the fadein and fadeout
functions.
I made a script to fade in a list when the mouse is over an image but
it dosen't work at all.
I want to make an action where when the users put the mouse over the
image a window fades in it could be a window/or table/ ect somthing
that will look like a photo album which allows the user to look at
other pics the users has then if the users mouse goes off the picture
and it's not on that fadeded in table/or window then it would fade
out.
I am trying to play with my css elements I already defined all html
elements to css properties ect.- Hide quoted text -
- Show quoted text -
