I also want to add in I am making a javascript file meaning myscode.js and I included it in my website which is in html.
once I do that would it run the js ???? or do I have to do a special call using <script> tags to call functions or var again from the script to run any javascript on the html doc?? On May 4, 5:42 pm, Aaron <[EMAIL PROTECTED]> wrote: > No not a drop down. I want it just like a table or look how a tool tip > looks but I want the stuff inside the table area to be clickable. > Like I have a photo of a person and I want that person to be able to > put the mouse over the photo to fade in their photo album with other > photos in a sqaure window. > > the li is the list of photos of the user. > > Here is a somewhat > example:http://www.tamingthebeast.net/articles6/tooltip-scripts-uses.htm > > I want somthing like a tooltip but I want it to show photos where a > user can scroll and see a whole photo album. > > On May 4, 1:43 pm, Eddie <[EMAIL PROTECTED]> wrote: > > > > > Is it like dropdown menu? Your markup is made of nested lists, right? > > > On 4 maio, 11:25, Liam Byrne <[EMAIL PROTECTED]> wrote: > > > > What's "li" meant to be - in that code it's not assigned at all.... > > > > If it's meant to be "every list item on the page", then it should be > > > $("li"), and you'll also need to check whether or not the outer "ul" or > > > "ol" for the li is visible. > > > > Liam > > > > Aaron wrote: > > > > well I don't plan using a class I am trying to use an id. in css I > > > > have stuff declared like #image{css stuff here;} > > > > here is the code I have. > > > > > $("#image").hover( > > > > function(){ > > > > $(li).fadeIn("slow"); > > > > }, > > > > function(){ > > > > $(li).fadeOut("slow"); > > > > }, > > > > ); > > > > > what I want to do is when the mouse goes over the image I want a > > > > window not a popup window but a window that fades in on the right or > > > > left of the image where it would have a list of other images and if > > > > the mouse goes off the image and is not on that list area then it > > > > would fade out. > > > > > -------------------------------------------------------------------------------------------------------- > > > > On May 3, 8:15 pm, Eddie <[EMAIL PROTECTED]> wrote: > > > > >> Hi Aaron, > > > > >> Try this: > > > > >> $(".elementClass").hover( > > > >> function(){ > > > >> $(this).fadeIn("normal"); > > > >> }, > > > >> function(){ > > > >> $(this).fadeOut("normal"); > > > >> }, > > > >> ); > > > > >> If it's not what you expected, post your code. > > > > >> On 3 maio, 17:50, Aaron <[EMAIL PROTECTED]> wrote: > > > > >>> Hi I am somewhat new here and to jquery I learned javascript and have > > > >>> a previous knowledge of programming. > > > > >>> I am having trouble using the hover and the fadein and fadeout > > > >>> functions. > > > > >>> I made a script to fade in a list when the mouse is over an image but > > > >>> it dosen't work at all. > > > > >>> I want to make an action where when the users put the mouse over the > > > >>> image a window fades in it could be a window/or table/ ect somthing > > > >>> that will look like a photo album which allows the user to look at > > > >>> other pics the users has then if the users mouse goes off the picture > > > >>> and it's not on that fadeded in table/or window then it would fade > > > >>> out. > > > > >>> I am trying to play with my css elements I already defined all html > > > >>> elements to css properties ect.- Hide quoted text - > > > > >> - Show quoted text -- Hide quoted text - > > > - Show quoted text -- Hide quoted text - > > - Show quoted text -
