1. you can acces them like this $('tr td', this).each(...); Also see
here for custom plugins and functions:
http://jquery-howto.blogspot.com/search/label/plugin
2. when you use $('table') you'll get a selection of all tables. If
you do this you would get the same object instance:
var $table = $('table');
$table.table();
$table.TableSetTitles({col1:"test", col3: "test3", col5: "notexist"});
3. if a function takes an argument pass it a $table as parameter ...
(give us a concrete example, and we could give a proper answer to this
question...)
----
Read jQuery HowTo Resource - http://jquery-howto.blogspot.com
On Sat, Feb 7, 2009 at 10:22 AM, ShurikAg <shuri...@gmail.com> wrote:
>
> Hi,
>
> 1.
> Assume that there is a table on a page:
> <table>
> <tr>
> <td></td>
> <td></td>
> </tr>
> </table>
>
> and I'm using jQuery to manipulate this table by:
> $("table").table();
>
> What is the right way of accessing "td" elements inside the function:
> (function(jQ) {
> jQ.fn.table = function(options, titles, data){
> ...
> ...
> }
> })(jQuery);
>
> 2.
> When I'm accessing the same table outside of plugin, like this:
> $("table").table();
> $("table").TableSetTitles({col1:"test", col3: "test3", col5:
> "not
> exist"});
> Do I actually accessing the same object instance? If not, what is the
> right way of doing it?
>
> 3.
> If I need to use additional jQuery object (.ajax for instance) by
> passing the table object to it; what is the right way of doing it?
>
> Thank you in advance.
