Looks like your first two offerings throw this error in Firebug:
"unlabeled break must be inside loop or switch"
Your last example works but it only works on the first TR and it
affects both TD's in that TR. ??
On Jun 24, 10:59 am, Matthew <mvbo...@gmail.com> wrote:
> yeah haha let me re-do:
>
> $("table#id tr:first-child").each(function(){
> $(this).attr("attribute","value");
>
> });
>
> try that. I am thinking that the tr:first-child should return the TD
> for every TR in the table. Im not sure how this will work if you have
> nested tables. I'm at work so I cant spend the time to test the code
> before hand.
>
> On Jun 24, 10:50 am, MikeyJ <m.en...@gmail.com> wrote:
>
> > Thx Matthew! Great explanation.
>
> > I probably should have worded one thing a bit differently...I'd like
> > to set this attribute for "the first TD in each TR for EVERY TR in an
> > entire table". I'm sure this changes things a tiny bit?
>
> > Mike
>
> > On Jun 24, 10:43 am, Matthew <mvbo...@gmail.com> wrote:
>
> > > when you use this code $("tr td") it would create an array of all
> > > those td's in the tr. So then we just need to cycle through the first
> > > two and set the attribute then break the cycle.
>
> > > var counter = 0;
> > > $("tr td").each(function(){
> > > $(this).attr("attribute","value");
> > > counter++;
> > > if(counter > 1) { break; } // after the first two td's stop
> > > the iteration through all the td's.
>
> > > });
>
> > > You can be more specific with what tr you use or you could use a table
> > > with a certain class or id:
>
> > > $("table.class tr td").each(........
>
> > > hope this helps.
>
> > > On Jun 24, 10:26 am, MikeyJ <m.en...@gmail.com> wrote:
>
> > > > Hi All,
>
> > > > I'd like to set the align attribute of only the first TD in a TR for
> > > > an entire table but am not sure how to address them all in one go.
> > > > Probably an Nth child thing or similar but not sure!
>
> > > > Thx,
> > > > Mike
>
>
