Sweet, thanks Charlie...
Charlie, how did you find out about: $("td:first",this)? In the
jquery docs i havent seen the ",this" I'm assuming that adding that
filters out the first td of each tr, I'd be interesting in knowing
more about how to filter things. Looks like I could make most of my
code way more efficient.
On Jun 24, 11:35 am, MikeyJ <m.en...@gmail.com> wrote:
> No prob! Looks like you are real close to what Charlie just posted
> that works great, except that it applies to every table on the page.
> Once I added the table id it was perfect!
>
> $("table#mytableid tr").each(function() {
> $("td:first",this).attr("align","right");
>
> });
>
> On Jun 24, 11:31 am, Matthew <mvbo...@gmail.com> wrote:
>
> > sorry about the error, replace "break;" with "return false;" Yeah,
> > ignore the last code then. Try this, I'm trying to find a way of doing
> > this cleanly so I guess we are both learning together haha
>
> > $("table tr").each(function(){
> > $(this).children(":first").attr("attribute","value");
>
> > });
>
> > On Jun 24, 11:14 am, MikeyJ <m.en...@gmail.com> wrote:
>
> > > Looks like your first two offerings throw this error in Firebug:
>
> > > "unlabeled break must be inside loop or switch"
>
> > > Your last example works but it only works on the first TR and it
> > > affects both TD's in that TR. ??
>
> > > On Jun 24, 10:59 am, Matthew <mvbo...@gmail.com> wrote:
>
> > > > yeah haha let me re-do:
>
> > > > $("table#id tr:first-child").each(function(){
> > > > $(this).attr("attribute","value");
>
> > > > });
>
> > > > try that. I am thinking that the tr:first-child should return the TD
> > > > for every TR in the table. Im not sure how this will work if you have
> > > > nested tables. I'm at work so I cant spend the time to test the code
> > > > before hand.
>
> > > > On Jun 24, 10:50 am, MikeyJ <m.en...@gmail.com> wrote:
>
> > > > > Thx Matthew! Great explanation.
>
> > > > > I probably should have worded one thing a bit differently...I'd like
> > > > > to set this attribute for "the first TD in each TR for EVERY TR in an
> > > > > entire table". I'm sure this changes things a tiny bit?
>
> > > > > Mike
>
> > > > > On Jun 24, 10:43 am, Matthew <mvbo...@gmail.com> wrote:
>
> > > > > > when you use this code $("tr td") it would create an array of all
> > > > > > those td's in the tr. So then we just need to cycle through the
> > > > > > first
> > > > > > two and set the attribute then break the cycle.
>
> > > > > > var counter = 0;
> > > > > > $("tr td").each(function(){
> > > > > > $(this).attr("attribute","value");
> > > > > > counter++;
> > > > > > if(counter > 1) { break; } // after the first two td's stop
> > > > > > the iteration through all the td's.
>
> > > > > > });
>
> > > > > > You can be more specific with what tr you use or you could use a
> > > > > > table
> > > > > > with a certain class or id:
>
> > > > > > $("table.class tr td").each(........
>
> > > > > > hope this helps.
>
> > > > > > On Jun 24, 10:26 am, MikeyJ <m.en...@gmail.com> wrote:
>
> > > > > > > Hi All,
>
> > > > > > > I'd like to set the align attribute of only the first TD in a TR
> > > > > > > for
> > > > > > > an entire table but am not sure how to address them all in one go.
> > > > > > > Probably an Nth child thing or similar but not sure!
>
> > > > > > > Thx,
> > > > > > > Mike
