70 MPH = 6160 FPM = 2.3656 inches water col. velocity pressure = 0.6061 kpa [standard air conditions] Do the conversions yourself.
My Rocky Mountain ASI can be programmer to do the same thing using solid state relays. KRron ----- Original Message ----- From: "Dene Collett (SA)" <dene.coll...@telkomsa.net> To: "krnet" <kr...@mylist.net> Sent: Monday, April 12, 2004 2:06 PM Subject: KR> 2 pitot questions > Hi again gang, I had the oppertunity yesterday to take a good look at a > Lancair360 and saw two things that interested me. On the landing gear > (retract) they do not make use of the conventional squat switch using a > microswitch mounted somewhere on the retract mechanism but use of a pressure > switch connected to the pitot line. this switch will not close the contact > untill it sees a pitot pressure that represents 70mph. My question is : What > pressure will 70mph create in the pitot line. I know it is actually the > differential pressure between the pitot and the static port. What would it > be in inches mercury/mm water. > My second observation was that the static port is located on the fuselage > side behind the pilot. Has anyone used this location for the static port? My > thoughts are that this would be a low pressure area??? > Dene Collett > KR2S-RT builder > Port Elizabeth > South Africa > mailto: dene.coll...@telkomsa.net > P.S: checkout www.whisperaircraft.com > > > > _______________________________________ > to UNsubscribe from KRnet, send a message to krnet-le...@mylist.net > please see other KRnet info at http://www.krnet.org/info.html > >
