Its pounds feet. Here's my understanding of it.
If you imagine a 2ft diam pulley attached to your engine,with a 110lb weight hung on a rope wound around the pulley, then the engine will lift the weight at the rated max torque rpm. Example. If an engine is rated are 110 lbft at 2500revs 2 x pi x 2500 revs approx 15500 ft/min. The engine will not be able to lift 120lb so fast, the engine torque graph will show how fast the engine can turn. One horse power lifts 110 lb at 5 ft/sec = 300 ft/min so engine power would be 15500/300. = 51 hp at 2500. Max torque is always generated at less than max pwr as friction increases at a rate greater that engine speed increases. So I sort of guess that best rate of climb is achieved at Max torque revs. Pete -- Sent from my Android phone with K-9 Mail. Please excuse my brevity. Glenn Martin <rep...@martekmississippi.com> wrote: On 8/28/2011 3:11 PM, Dan Heath wrote: > Glenn, > > The 2180 VW is said to produce 76HP at 3600 RPM, so, it would produce 110.88 > "whatever torques are". This is without respect to prop. > Torque is in inch-lbs per foot -- Glenn Martin _____________________________________________ Search the KRnet Archives at http://www.maddyhome.com/krsrch/index.jsp to UNsubscribe from KRnet, send a message to krnet-le...@mylist.net please see other KRnet info at http://www.krnet.org/info.html
