I don't understand exactly what you want... So can you send me your .dir (if
it is not too large) at my private adress ?
Pat : [EMAIL PROTECTED]
-----Message d'origine-----
De : [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]De la
part de Ravi Garimella
Envoyé : jeudi 1 mars 2001 19:48
À : [EMAIL PROTECTED]
Objet : Re: <lingo-l> Field Values and Multiple Choice Answers
Thanks Rich and Pat, but this actually does not solve my problem.
My field where answers are stored is like this
Answer 1,answer 2,answer newanswer,answer;
answer 2,answer3,answer4,new answer;
and my output would be like this
Answer 1
Answer 2
Answer Newanswer
answer
The problem is to get the space between 2 words which i am not able to get
it.
Any help on this would be appreciated.
ravi
>Ravi,
>
>I can't tell how the handler is called or when the question num is
>incremented.
>
>To keep your answer direct, I'll assume that each line in the answers
>field contains all answers for each question, that gQuestionNum is
>assigned elsewhere, and that your destination field is related to the
>question.
>
>All you really need to do is add the RETURN constant after each answer.
>Below, I've added two niceties. First, I've stored the old itemDelimiter
>("," by default) and restored it after every switch, in case you ever
>need to use the default behavior eslewhere. This prevents the need to
>switch it again later back to the comma. This is not needed to answer
>your question. Secondly, I've only put a RETURN after the answer if it's
>NOT the last answer in the field. This prevents an extra return from
>being added to the end of the field.
>
>Also, don't forget that your item delimiter doesn't include spaces. If
>your answers are "answer1;answer2;answer3;answer4" you'll be fine. But,
>if they're "answer1; answer2; answer3; answer4", you will have a space as
>the first character for answers 2-4.
>
>I hope you can adapt this to your needs.
>
>on showAnswer
> oldDelim = the itemDelimiter
> the itemDelimiter = ";"
> text = member("answers").text.line[gQuestionNum]
> repeat with x = 1 to text.item.count
> if x = text.item.count then
> member("testField").text = member("testField").text & text.item[x]
> else
> member("testField").text = member("testField").text & text.item[x]
>& RETURN
> end if
> end repeat
> the itemDelimiter = oldDelim
> gQuestionNum = gQuestionNum + 1
>end
>
>Rich Shupe
>
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