> example may have been lame, but the point was that working
> backward from
> value was no guarantee that you got the matching property.
Hmm.. I see your point now. Actually, that would also be true for a properly
structured list, such as:
[#name: "Joe", #password: "Joe", #age: 3]
It's still not a problem for Kerry's example (he only has one property per
sub-list, so it can't conflict with anything else), but for any list that
has more then one property in it, my approach is potentially buggy.
on propLst, myProp
mainList = [ [#puzzle: [ [#title: "One"], [#level: "Moderate"], [#word:
"Lingo"], [#word: "Director"] ] ], [#puzzle: [ [#title: "Two"], [level:
"Beginner"], [#word: "Action"], [#word: "Flash"] ] ] ]
repeat with subList1 in mainList
repeat with subList2 in subList1
repeat with subList3 in subList2
iMax = sublist3.count
repeat with i = 1 to iMax
if subList3.getPropAt(i) = myProp then
put sublist3[i]
end if
end repeat
end repeat
end repeat
end repeat
end
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