On 29-Jan 17:36, Peter Zijlstra wrote:
> On Tue, Jan 23, 2018 at 06:08:45PM +0000, Patrick Bellasi wrote:
> > +static inline void util_est_dequeue(struct task_struct *p, int flags)
> > +{
> > +   struct cfs_rq *cfs_rq = &task_rq(p)->cfs;
> > +   unsigned long util_last = task_util(p);
> > +   bool sleep = flags & DEQUEUE_SLEEP;
> > +   unsigned long ewma;
> > +   long util_est = 0;
> > +
> > +   if (!sched_feat(UTIL_EST))
> > +           return;
> > +
> > +   /*
> > +    * Update root cfs_rq's estimated utilization
> > +    *
> > +    * If *p is the last task then the root cfs_rq's estimated utilization
> > +    * of a CPU is 0 by definition.
> > +    */
> > +   if (cfs_rq->nr_running) {
> > +           util_est  = READ_ONCE(cfs_rq->util_est_runnable);
> > +           util_est -= min_t(long, util_est, task_util_est(p));
> > +   }
> > +   WRITE_ONCE(cfs_rq->util_est_runnable, util_est);
> > +
> > +   /*
> > +    * Skip update of task's estimated utilization when the task has not
> > +    * yet completed an activation, e.g. being migrated.
> > +    */
> > +   if (!sleep)
> > +           return;
> > +
> 
> Since you only use sleep once, you might as well write it out there.

Right, will move the flag check right here.

> Also, does GCC lower the task_util() eval to here?

Good point, kind-of... on ARM64 it generates a register load just before
the above if condition. I guess it does that to speculatively trigger a
load from memory in case the above check should pass?

Anyway, looks more it can be also a micro-arch optimization.
Thus, even just for better readability of the following chunk, it's
better to move the util_last definition here.

> > +        /*
> > +         * Skip update of task's estimated utilization when its EWMA is 
> > already
> > +         * ~1% close to its last activation value.
> > +         */
> > +        util_est = p->util_est.ewma;
> > +        if (abs(util_est - util_last) <= (SCHED_CAPACITY_SCALE / 100))
> > +                return;
> 
> Aside from that being whitespace challenged, did you also try:
> 
>       if ((unsigned)((util_est - util_last) + LIM - 1) < (2 * LIM - 1))

No, since the above code IMO is so much "easy to parse for humans" :)
But, mainly because since the cache alignment update, also while testing on a
"big" Intel machine I cannot see regressions on hackbench.

This is the code I get on my Xeon E5-2690 v2:

       if (abs(util_est - util_last) <= (SCHED_CAPACITY_SCALE / 100))
   6ba0:       8b 86 7c 02 00 00       mov    0x27c(%rsi),%eax
   6ba6:       48 29 c8                sub    %rcx,%rax
   6ba9:       48 99                   cqto
   6bab:       48 31 d0                xor    %rdx,%rax
   6bae:       48 29 d0                sub    %rdx,%rax
   6bb1:       48 83 f8 0a             cmp    $0xa,%rax
   6bb5:       7e 1d                   jle    6bd4 <dequeue_task_fair+0x7e4>

Does it look so bad?

> Also, since we only care about the absolute value; we could use:
> 
>       util_last - ewma
> 
> here (note the above also forgets to use READ_ONCE), and reuse the result:
> 
> > +
> > +   /*
> > +    * Update Task's estimated utilization
> > +    *
> > +    * When *p completes an activation we can consolidate another sample
> > +    * about the task size. This is done by storing the last PELT value
> > +    * for this task and using this value to load another sample in the
> > +    * exponential weighted moving average:
> > +    *
> > +    *      ewma(t) = w *  task_util(p) + (1 - w) ewma(t-1)
> > +    *              = w *  task_util(p) + ewma(t-1) - w * ewma(t-1)
> > +    *              = w * (task_util(p) + ewma(t-1) / w - ewma(t-1))
> > +    *
> > +    * Where 'w' is the weight of new samples, which is configured to be
> > +    * 0.25, thus making w=1/4
> > +    */
> > +   p->se.avg.util_est.last = util_last;
> > +   ewma = READ_ONCE(p->se.avg.util_est.ewma);
> > +   ewma   = util_last + (ewma << UTIL_EST_WEIGHT_SHIFT) - ewma;
> 
> here.

Right! +1

> 
> > +   ewma >>= UTIL_EST_WEIGHT_SHIFT;
> > +   WRITE_ONCE(p->se.avg.util_est.ewma, ewma);
> > +}
> 
> So something along these lines:
> 
>       ewma = READ_ONCE(p->se.avg.util_est.ewma);
>       diff = util_last - ewma;
>       if ((unsigned)(diff + LIM - 1) < (2 * LIM - 1))
>               return;
> 
>       p->se.avg.util_est.last = util_last;
>       ewma = (diff + (ewma << EWMA_SHIFT)) >> EWMA_SHIFT;
>       WRITE_ONCE(p->se.avg.util_est.ewma, ewma);
> 
> Make sense?

Looks ok to me, I will for sure update to reuse the difference.

Regarding the comparison, I'll try your formula to check again if there is any
noticeable difference on hackbench.

Thanks Patrick

-- 
#include <best/regards.h>

Patrick Bellasi

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