On Thu, 31 Dec 1998 21:51:21 +0500,
"Irfan Akber" <[EMAIL PROTECTED]> wrote:
>What is the rule for supernetting 2-3 subnets to appear as one single
>block.
>e.g I have 4 subnets of 192.168.1.0 giving 4 subnets each with 62 usable
A subnet must have n leading 1's in its netmask. Therefore it contains
2**(32-n) addresses. Grab ftp://ftp.ocs.com.au/ipcalc.pl.gz (Perl 5)
or ipcalc.tcl.gz (Tcl/Tk 8).
ipcalc.pl 192.168.1.0/26
IP address 192 . 168 . 1 . 0 / 26 192.168.1.0/26
Netmask bits 11111111 11111111 11111111 11000000
Netmask bytes 255 . 255 . 255 . 192 255.255.255.192
Address bits 11000000 10101000 00000001 00000000
Network 192 . 168 . 1 . 0 192.168.1.0
Broadcast 192 . 168 . 1 . 63 192.168.1.63
First Host 192 . 168 . 1 . 1 192.168.1.1
Last Host 192 . 168 . 1 . 62 192.168.1.62
Total Hosts 62
PTR 0.1.168.192.in-addr.arpa
IP Address (hex) C0A80100
ipcalc.pl 192.168.1.128/25
IP address 192 . 168 . 1 . 128 / 25 192.168.1.128/25
Netmask bits 11111111 11111111 11111111 10000000
Netmask bytes 255 . 255 . 255 . 128 255.255.255.128
Address bits 11000000 10101000 00000001 10000000
Network 192 . 168 . 1 . 128 192.168.1.128
Broadcast 192 . 168 . 1 . 255 192.168.1.255
First Host 192 . 168 . 1 . 129 192.168.1.129
Last Host 192 . 168 . 1 . 254 192.168.1.254
Total Hosts 126
PTR 128.1.168.192.in-addr.arpa
IP Address (hex) C0A80180
The best you can do is join subnets 3 and 4 together. Joing 2, 3 and 4
would give 192 addresses which is not a power of two therefore you
cannot join 2, 3, and 4.
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