Yes that's partially right, but the output isn't as high as a generator as the rated horsepower output. Due to losses. If memory serves, for every rated horsepower ~750watts is equivalent. Since the motor isn't designed to function as a generator. There's some internal loss. You can compensate for that by overdriving the motors rated rpm. So for a 3hp rated electric motor, you could yield close to 2200watts. (IE motor rated for 1800rpm being turned at 2K rpm rated at 3hp would create the 2200watts mentioned. The ICE engine would need to be larger than 3hp to drive or geared to compensate)
Andrew On Tue, Apr 1, 2008 at 4:53 PM, john fisher <[EMAIL PROTECTED]> wrote: > focussing on the connecting the genset to the battery pack: > > jeff said > > If it is a normal AC genset you have the AC (120/240) to DC conversion > > losses through your charger. Ideally if you find a DC genset that can > > output near 85VDC, or modify a genset to output directly to 85VDC you > > can minimize your losses. > > > > Jeff > > so in looking at DC motors to use as a generator. > Is it reasonable to work backwards from the motor input to figure out the > likely generator output? For instance, if I > see a DC motor that makes 3hp at say 3000 rpm ( pulling numbers out of the > air here) and requires about 3Kw to do it, is > it reasonable to assume a 4hp ( allowing for losses) ICE driving the same > motor at 3000 rpm will produce about 3Kw, more > or less? > > John > >
