If you figure watts are watts, take the number of watts required by the drive motor to maintain a speed, let's say 45 mph - 50A @ 72 V = 3600 watts, so I would then look at the power plant paired with the generator on a commercially available unit, you may well find a higher horsepower engine than you are proposing, then again maybe not.
Jeff On Tue, Apr 1, 2008 at 2:53 PM, john fisher <[EMAIL PROTECTED]> wrote: > focussing on the connecting the genset to the battery pack: > > jeff said > > If it is a normal AC genset you have the AC (120/240) to DC conversion > > losses through your charger. Ideally if you find a DC genset that can > > output near 85VDC, or modify a genset to output directly to 85VDC you > > can minimize your losses. > > > > Jeff > > so in looking at DC motors to use as a generator. > Is it reasonable to work backwards from the motor input to figure out the > likely generator output? For instance, if I > see a DC motor that makes 3hp at say 3000 rpm ( pulling numbers out of the > air here) and requires about 3Kw to do it, is > it reasonable to assume a 4hp ( allowing for losses) ICE driving the same > motor at 3000 rpm will produce about 3Kw, more > or less? > > John > >
