Eric Firing wrote:
>> Specifically, what I have is an array like so:
>>
>> ['','','',1.1,2.2]
>
> Try something like this:
>
> import numpy.ma as ma
> from pylab import *
>
> aa = [3.4, 2.5, '','','',1.1,2.2]
> def to_num(arg):
> if arg == '':
> return 9999.0
> return arg
>
> aanum = array([to_num(arg) for arg in aa])
> aamasked = ma.masked_where(aanum==9999.0, aanum)
> plot(aamasked)
> show()
What I ended up doing was getting my array to look like:
from numpy import nan
aa = [3.4,2.5,nan,nan,nan,1.1,2.2]
values = numpy.array(aa)
values = numpy.ma.masked_equal(values,nan)
I only wish that masked_equal didn't blow up when aa contains datetime
objects :-(
cheers,
Chris
--
Simplistix - Content Management, Zope & Python Consulting
- http://www.simplistix.co.uk
-------------------------------------------------------------------------
This SF.net email is sponsored by: Microsoft
Defy all challenges. Microsoft(R) Visual Studio 2008.
http://clk.atdmt.com/MRT/go/vse0120000070mrt/direct/01/
_______________________________________________
Matplotlib-users mailing list
Matplotlib-users@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/matplotlib-users
