Chris, thank you very much for your reply. I encountered a related
error, and was hoping you could help me understand this one too...
Using ipython -pylab I run the script below to generate a GUI, but
when the GUI finishes running (after 3 button clicks), ipython crashes
with the following error message: "Segmentation fault". This error
does not occur if I remove the call to pyplot.close in
myGUI.disconnect, nor does it occur if I use a key_press_event instead
of a button_press_event.
Why is an error generated when I try to close the figure?
Why does this error occur for button_press_events but not
key_press_events?
from numpy.random import rand
from matplotlib import pyplot
class myGUI:
def __init__(self,x):
self.fig = pyplot.gcf()
self.n = 0
self.connect()
pyplot.plot(x)
pyplot.show()
def connect(self):
self.cidbuttonpress =
self.fig.canvas.mpl_connect('button_press_event', self.buttonpress)
def disconnect(self):
self.fig.canvas.mpl_disconnect(self.cidbuttonpress)
pyplot.close(self.fig)
def buttonpress(self,event):
self.n += 1
if self.n >=2:
self.disconnect()
pyplot.figure()
obj = myGUI(rand(10))
On 22 May 2009, at 00:49, Christopher Barker wrote:
Todd Pataky wrote:
> I'm using the Enthought Python Distribution (EPD_Py25) and I enter
> IPython with the command: "ipython".
....
> This problem does not occur if I use EPD's PyLab (i.e. "ipython -
> pylab"). Does anyone know why?
because the whole point of the "pylab" flag to ipython is to tell
ipython to start up the MPL plotting stuff in separate thread so that it
can work like you want it to. If you don't' use that flag, then each
call to pyplot tries to start up a new app, ,but the old one is still
running, hence you problems.
ipython itself can be used for all sort of things that have nothing to
do with matplotlib, so that's not its default behavior.
Just use ipython -pylab if you want to do interactive plotting, that's
what it's for.
-Chris
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