what name type matlab program can run this my matlab R2013a dont's run On 26 October 2016 at 07:26, Saranya A <asar...@gmail.com> wrote:
> Hi Nur, > Dont divide R and X with the voltage. I get the following power flow > without those two lines. > > ------------ > runpf('LV10') > > MATPOWER Version 6.0b1, 01-Jun-2016 -- AC Power Flow (Newton) > > Newton's method power flow converged in 5 iterations. > > Converged in 0.02 seconds > ============================================================ > ==================== > | System Summary > | > ============================================================ > ==================== > > How many? How much? P (MW) Q (MVAr) > --------------------- ------------------- ------------- > ----------------- > Buses 12 Total Gen Capacity 261.0 -302.0 to > 302.0 > Generators 11 On-line Capacity 250.0 -300.0 to > 300.0 > Committed Gens 1 Generation (actual) 1.2 0.5 > Loads 10 Load 1.0 0.3 > Fixed 10 Fixed 1.0 0.3 > Dispatchable 0 Dispatchable -0.0 of -0.0 -0.0 > Shunts 0 Shunt (inj) -0.0 0.0 > Branches 11 Losses (I^2 * Z) 0.23 0.16 > Transformers 0 Branch Charging (inj) - 0.0 > Inter-ties 0 Total Inter-tie Flow 0.0 0.0 > Areas 1 > > Minimum Maximum > ------------------------- ----------------------------- > --- > Voltage Magnitude 0.717 p.u. @ bus 11 1.000 p.u. @ bus 1 > Voltage Angle -5.40 deg @ bus 11 0.00 deg @ bus 1 > P Losses (I^2*R) - 0.06 MW @ line 1-2 > Q Losses (I^2*X) - 0.04 MVAr @ line 1-2 > > ============================================================ > ==================== > | Bus Data > | > ============================================================ > ==================== > Bus Voltage Generation Load > # Mag(pu) Ang(deg) P (MW) Q (MVAr) P (MW) Q (MVAr) > ----- ------- -------- -------- -------- -------- -------- > 1 1.000 0.000* 1.23 0.46 - - > 2 0.950 -0.744 - - 0.10 0.03 > 3 0.905 -1.483 - - 0.10 0.03 > 4 0.864 -2.206 - - 0.10 0.03 > 5 0.828 -2.898 - - 0.10 0.03 > 6 0.797 -3.541 - - 0.10 0.03 > 7 0.770 -4.116 - - 0.10 0.03 > 8 0.749 -4.607 - - 0.10 0.03 > 9 0.733 -4.993 - - 0.10 0.03 > 10 0.722 -5.260 - - 0.10 0.03 > 11 0.717 -5.397 - - 0.10 0.03 > 12 1.000 0.000 - - - - > -------- -------- -------- -------- > Total: 1.23 0.46 1.00 0.30 > > ============================================================ > ==================== > | Branch Data > | > ============================================================ > ==================== > Brnch From To From Bus Injection To Bus Injection Loss (I^2 * > Z) > # Bus Bus P (MW) Q (MVAr) P (MW) Q (MVAr) P (MW) Q > (MVAr) > ----- ----- ----- -------- -------- -------- -------- -------- > -------- > 1 1 2 1.23 0.46 -1.17 -0.42 0.055 > 0.04 > 2 2 3 1.07 0.39 -1.03 -0.36 0.046 > 0.03 > 3 3 4 0.93 0.33 -0.89 -0.30 0.038 > 0.03 > 4 4 5 0.79 0.27 -0.76 -0.25 0.030 > 0.02 > 5 5 6 0.66 0.22 -0.64 -0.20 0.023 > 0.02 > 6 6 7 0.54 0.17 -0.52 -0.16 0.016 > 0.01 > 7 7 8 0.42 0.13 -0.41 -0.13 0.011 > 0.01 > 8 8 9 0.31 0.10 -0.30 -0.09 0.006 > 0.00 > 9 9 10 0.20 0.06 -0.20 -0.06 0.003 > 0.00 > 10 10 11 0.10 0.03 -0.10 -0.03 0.001 > 0.00 > 11 1 12 0.00 0.00 0.00 0.00 0.000 > 0.00 > -------- > -------- > Total: 0.228 > 0.16 > > On Tue, Oct 25, 2016 at 10:31 PM, Nazurah Nasir <nurnazu...@gmail.com> > wrote: > >> >> >> Hi all MatPower community, >> >> I am trying to develop a simple LV network in radial network >> distribution. However, my model did not converge or if I scale the R and X, >> the results is too big (which means the R,X) scaling is wrong. I tried for >> one month now but still could get around why it is not converging. >> >> I need to work on this PowerFlow to work inside my bilevel programming >> loop. but it seems my code won't work because the power flow is not >> converging. >> >> I need help on verifying my parameter. Attached is my code that I build. >> As the MatPower is in three phase balanced, I lumped my loads that >> connected to a bus as one load, hence the voltage at the bus is 0.415kV. My >> input power are all in kW, hence I change the impedance values accordingly >> by multiplying it by 1000. The input power is just a dummy value of 0.1MW >> because it will update itself in a loop. But since input power is in kW, I >> should divide that by 1000 right? >> >> Thank you so much for the help. >> >> >> Best regards, >> Nur >> >> >