But does that means I should not divide my input power data by 1000 to make
it in MW? If I do that, it won't converge. For example, these are my Power
input for one time:
Columns 1 through 6
1.0000 3.0000 0 0 0 0
2.0000 1.0000 0.0012 0.0004 0 0
3.0000 1.0000 0.0019 0.0006 0 0
4.0000 1.0000 0.0006 0.0002 0 0
5.0000 1.0000 0.0024 0.0008 0 0
6.0000 1.0000 0.0012 0.0004 0 0
7.0000 1.0000 0.0010 0.0003 0 0
8.0000 1.0000 0.0023 0.0008 0 0
9.0000 1.0000 0.0005 0.0002 0 0
10.0000 1.0000 0.0006 0.0002 0 0
11.0000 1.0000 0.0012 0.0004 0 0
12.0000 1.0000 0 0 0 0
Columns 7 through 12
1.0000 1.0000 0 0.4150 1.0000 1.1000
1.0000 1.0000 0 0.4150 1.0000 1.1000
1.0000 1.0000 0 0.4150 1.0000 1.1000
1.0000 1.0000 0 0.4150 1.0000 1.1000
1.0000 1.0000 0 0.4150 1.0000 1.1000
1.0000 1.0000 0 0.4150 1.0000 1.1000
1.0000 1.0000 0 0.4150 1.0000 1.1000
1.0000 1.0000 0 0.4150 1.0000 1.1000
1.0000 1.0000 0 0.4150 1.0000 1.1000
1.0000 1.0000 0 0.4150 1.0000 1.1000
1.0000 1.0000 0 0.4150 1.0000 1.1000
1.0000 1.0000 0 0.4150 1.0000 1.1000
Column 13
0.9400
0.9400
0.9400
0.9400
0.9400
0.9400
0.9400
0.9400
0.9400
0.9400
0.9400
0.9400
Thank you very much for the help
Yours sincerely,
Nur
On Wed, Oct 26, 2016 at 11:14 PM, Nazurah Nasir <nurnazu...@gmail.com>
wrote:
> Aren't I supposed to make the R and X in p.u. if I want to use them in
> MATPOWER? Regardless, your simulation seems to be more sensible. But, I
> just curious, so we don't necessarily change the R and X into p.u. values?
>
> Thanks for the response.
>
> On Wed, Oct 26, 2016 at 3:26 PM, Saranya A <asar...@gmail.com> wrote:
>
>> Hi Nur,
>> Dont divide R and X with the voltage. I get the following power flow
>> without those two lines.
>>
>> ------------
>> runpf('LV10')
>>
>> MATPOWER Version 6.0b1, 01-Jun-2016 -- AC Power Flow (Newton)
>>
>> Newton's method power flow converged in 5 iterations.
>>
>> Converged in 0.02 seconds
>> ============================================================
>> ====================
>> | System Summary
>> |
>> ============================================================
>> ====================
>>
>> How many? How much? P (MW) Q (MVAr)
>> --------------------- ------------------- -------------
>> -----------------
>> Buses 12 Total Gen Capacity 261.0 -302.0 to
>> 302.0
>> Generators 11 On-line Capacity 250.0 -300.0 to
>> 300.0
>> Committed Gens 1 Generation (actual) 1.2 0.5
>> Loads 10 Load 1.0 0.3
>> Fixed 10 Fixed 1.0 0.3
>> Dispatchable 0 Dispatchable -0.0 of -0.0 -0.0
>> Shunts 0 Shunt (inj) -0.0 0.0
>> Branches 11 Losses (I^2 * Z) 0.23 0.16
>> Transformers 0 Branch Charging (inj) - 0.0
>> Inter-ties 0 Total Inter-tie Flow 0.0 0.0
>> Areas 1
>>
>> Minimum Maximum
>> ------------------------- -----------------------------
>> ---
>> Voltage Magnitude 0.717 p.u. @ bus 11 1.000 p.u. @ bus 1
>> Voltage Angle -5.40 deg @ bus 11 0.00 deg @ bus 1
>> P Losses (I^2*R) - 0.06 MW @ line 1-2
>> Q Losses (I^2*X) - 0.04 MVAr @ line 1-2
>>
>> ============================================================
>> ====================
>> | Bus Data
>> |
>> ============================================================
>> ====================
>> Bus Voltage Generation Load
>> # Mag(pu) Ang(deg) P (MW) Q (MVAr) P (MW) Q (MVAr)
>> ----- ------- -------- -------- -------- -------- --------
>> 1 1.000 0.000* 1.23 0.46 - -
>> 2 0.950 -0.744 - - 0.10 0.03
>> 3 0.905 -1.483 - - 0.10 0.03
>> 4 0.864 -2.206 - - 0.10 0.03
>> 5 0.828 -2.898 - - 0.10 0.03
>> 6 0.797 -3.541 - - 0.10 0.03
>> 7 0.770 -4.116 - - 0.10 0.03
>> 8 0.749 -4.607 - - 0.10 0.03
>> 9 0.733 -4.993 - - 0.10 0.03
>> 10 0.722 -5.260 - - 0.10 0.03
>> 11 0.717 -5.397 - - 0.10 0.03
>> 12 1.000 0.000 - - - -
>> -------- -------- -------- --------
>> Total: 1.23 0.46 1.00 0.30
>>
>> ============================================================
>> ====================
>> | Branch Data
>> |
>> ============================================================
>> ====================
>> Brnch From To From Bus Injection To Bus Injection Loss (I^2
>> * Z)
>> # Bus Bus P (MW) Q (MVAr) P (MW) Q (MVAr) P (MW) Q
>> (MVAr)
>> ----- ----- ----- -------- -------- -------- -------- --------
>> --------
>> 1 1 2 1.23 0.46 -1.17 -0.42 0.055
>> 0.04
>> 2 2 3 1.07 0.39 -1.03 -0.36 0.046
>> 0.03
>> 3 3 4 0.93 0.33 -0.89 -0.30 0.038
>> 0.03
>> 4 4 5 0.79 0.27 -0.76 -0.25 0.030
>> 0.02
>> 5 5 6 0.66 0.22 -0.64 -0.20 0.023
>> 0.02
>> 6 6 7 0.54 0.17 -0.52 -0.16 0.016
>> 0.01
>> 7 7 8 0.42 0.13 -0.41 -0.13 0.011
>> 0.01
>> 8 8 9 0.31 0.10 -0.30 -0.09 0.006
>> 0.00
>> 9 9 10 0.20 0.06 -0.20 -0.06 0.003
>> 0.00
>> 10 10 11 0.10 0.03 -0.10 -0.03 0.001
>> 0.00
>> 11 1 12 0.00 0.00 0.00 0.00 0.000
>> 0.00
>> --------
>> --------
>> Total: 0.228
>> 0.16
>>
>> On Tue, Oct 25, 2016 at 10:31 PM, Nazurah Nasir <nurnazu...@gmail.com>
>> wrote:
>>
>>>
>>>
>>> Hi all MatPower community,
>>>
>>> I am trying to develop a simple LV network in radial network
>>> distribution. However, my model did not converge or if I scale the R and X,
>>> the results is too big (which means the R,X) scaling is wrong. I tried for
>>> one month now but still could get around why it is not converging.
>>>
>>> I need to work on this PowerFlow to work inside my bilevel programming
>>> loop. but it seems my code won't work because the power flow is not
>>> converging.
>>>
>>> I need help on verifying my parameter. Attached is my code that I build.
>>> As the MatPower is in three phase balanced, I lumped my loads that
>>> connected to a bus as one load, hence the voltage at the bus is 0.415kV. My
>>> input power are all in kW, hence I change the impedance values accordingly
>>> by multiplying it by 1000. The input power is just a dummy value of 0.1MW
>>> because it will update itself in a loop. But since input power is in kW, I
>>> should divide that by 1000 right?
>>>
>>> Thank you so much for the help.
>>>
>>>
>>> Best regards,
>>> Nur
>>>
>>>
>>
>
