Does anybody know if there is an exponent where the factor is, or know whether there is a proof on whether a factor can (or can't) be, a root?? A square?? To clarify this: We know that any factor of 2^p-1 is in the form 2kp+1. Letting x >=2, Can (2kp+1)^x = 2^p-1 ?? Can (2kp+1)^x * (2kp+1) ... = 2^p-1 ?? Eric Hahn _________________________________________________________________ Unsubscribe & list info -- http://www.scruz.net/~luke/signup.htm Mersenne Prime FAQ -- http://www.tasam.com/~lrwiman/FAQ-mers
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