Brian

For M1123 the factor 777288435261989969 using sigma = 1459848859275459 has 
a group order of 777288435636813540 = 2^2*3*5*11*31*1823*38917*535489 thus:

1. In stage 1: B1 >= 535489 is required

2. Noting that 534241 is 44147th prime and 535489 the 44230th prime;
   In stage 2: B1 >= 38917 is required and during stage 2 the block of
   primes for B2 >= 534241 happens to include the largest factor 535489.

Regards

Alan Powell   


At 02:17 PM 11/10/02, you wrote:
>Here's one example:
>
>With sigma=1459848859275459, Prime95 v22.12 finds the factor 
>777288435261989969 of M1123:
>
>in stage 1 with B1 >= 535489
>in stage 2 with B1 >= 38917 & B2 >= 534241
>
>I'm not entirely sure why the B2 required to find the factor at the end of 
>stage 2 is smaller than the B1 required to find it in stage 1. One of the 
>improvements I guess.

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