On Sunday 10 November 2002 20:03, [EMAIL PROTECTED] wrote:
> "Brian J. Beesley" <[EMAIL PROTECTED]> wrote
> - Here's one example:
> -
> - With sigma=1459848859275459, Prime95 v22.12 finds the factor
> - 777288435261989969 of M1123:
> -
> - in stage 1 with B1 >= 535489
> - in stage 2 with B1 >= 38917 & B2 >= 534241

And here are some more

With sigma=7324432520873427, the factor 649412561933038085071 of M1621 is 
found
- in stage 1 with B1 >= 2546119
- in stage 2 with B1 >= 94727, B2 >= 2543311

With sigma=5643809308022499, the factor 838124596866091911697 of M1787 is 
found
- in stage 1 with B1 >= 378041
- in stage 2 with B1 >= 35543, B2 >= 378001

With sigma=6305161669623833, the factor 597702354293770769 of M1867 is found
- in stage 1 with B1 >= 258983
- in stage 2 with B1 >= 3061, B2 >= 258301

With sigma=5956836392428930, the factor 8142767081771726171 of P721 is found
- in stage 1 with B1 >= 54779
- in stage 2 with B1 >= 33487, B2 >= 54390
>
>        How does one map sigma to a curve (and initial point)?
> What is the range of sigma (it seems to go beyond 2^32)?

At worst, RTFS. My reason for finding the critical B values was in the hope 
that someone with a better understanding of the algorithms and/or an 
independent ECM factoring program would be able to confirm that these values 
make sense.
>
>        The ECM tests should include a case where two primes are found at
> the same time during step 2, because the largest primes dividing the
> two group orders are equal.  [That is, the GCD will be composite.]
> This test may be hard to construct, however.

Actually, it's very easy.

The way I constructed the results submitted so far was to remove the known 
"target" factor from the low[mp].txt file & run a few curves with B1=10^5, B2 
automatic to find a sigma that "works". Not neccessarily the sigma that gives 
the lowest limits.

After receiving this message, I removed _all_ the known factors for P721. 
This was interesting, and indicates a bug, though it appears to be not very 
important:

with same sigma & minimum B1 & B2 noted above, the composite factor 129 
(= 3 * 43) was found. I would have expected (at least) 
3*43*8142767081771726171

Placing the known factors 3 & 43 back into lowp.txt and repeating the same 
curve yielded the expected factor 8142767081771726171.
>
>       Either the ECM tests or the p-1 tests should include a case where
> the group order (or p-1) is divisible by a power of a moderate prime,
> such as 61^3 or 757^2 .

There are lots of known examples for P-1.

Regards
Brian Beesley
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