Thanks For the help.... But looking at the following


OK here is the update:

Internet
     I
OpenBSD 4.2 (1) 10.60.0.1--- wired LAN
      I
wireless card - 10.60.128.1
      I
      I
      I
wireless card ral0 - 10.60.128.2
      I              netmask 255.255.192.0 
      I              broadcast 10.60.63.255
OpenBSD 4.2 (2)---- wired LAN em0 - 10.80.0.1 
      I             netmask 255.255.0.0 
      I             broadcast 10.80.255.255
wireless card ral1 - 10.70.0.1 
                     netmask 255.255.0.0  
                     broadcast 10.70.25.255

---------------------------------------------
I then added another wireless card to 

OpenBSD 4.2 (1) 
       I
Wireless Card (2)as 10.60.192.1 
netmask 255.255.192.0 
broadcast 10.60.255.255 
       I
       I
wireless card (2-1) 10.60.192.2
       I
       I
OpenBSD (3) 
       I
wired lan 10.90.0.1
netmask 255.255.0.0 
broadcast 10.90.255.255
       I
       I
host 10.90.0.2
netmask 255.255.0.0 
broadcast 10.90.255.255


So the question is.. will haveing the 10.90.0.0/16 subnet 
cause conflicts with the 10.70.0.0/16 and 10.80.0.0/16 networks 
on the OpenBSD (1) box's routing table.

Bret



Stuart Henderson wrote:

>On 2007/12/11 08:40, Bret wrote:
>  
>
>>OK here is the update:
>>    
>>
>
>  
>
>>ral0: flags=8843<UP,BROADCAST,RUNNING,SIMPLEX,MULTICAST> mtu 1500
>>    ieee80211: nwid tri-statebroadband.com_2 chan 3 bssid 
>>    inet 10.60.128.2 netmask 0xffffc000 broadcast 10.60.191.255
>>ral1: flags=8843<UP,BROADCAST,RUNNING,SIMPLEX,MULTICAST> mtu 1500
>>    ieee80211: nwid tri-statebroadband.com_2_1 chan 1 bssid 
>>    inet 10.60.129.1 netmask 0xffffc000 broadcast 10.60.191.255
>>em0: flags=8843<UP,BROADCAST,RUNNING,SIMPLEX,MULTICAST> mtu 1500
>>    media: Ethernet autoselect (100baseTX full-duplex,rxpause,txpause)
>>    inet 10.60.130.1 netmask 0xffffc000 broadcast 10.60.191.255
>>    
>>
>
>As I suspected, these are all in the same network.
>
>$ ipcalc 10.60.130.1/0xffffc000
>address   : 10.60.130.1     
>netmask   : 255.255.192.0   (0xffffc000)
>network   : 10.60.128.0     /18
>broadcast : 10.60.191.255   
>host min  : 10.60.128.1     
>host max  : 10.60.191.254   
>hosts/net : 16382
>
>Your chosen netmask makes the first 18 bits of the IP address be
>the network address, so 10.60.128 [...] 10.60.191 are all in the
>same network. This part of the address should be different between
>interfaces.

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