Thanks very much, Paul. Steve --- Paul Clarke <[EMAIL PROTECTED]> wrote: > >Thank you for your response. I had thought about > >minimizing the number of queues by 10 times -- like > >you just suggested. But, I did not know how to go > >about it. Sorry but, I seem to fail to understand > your > >above explanation. Can you please bear with me and > >explain a bit more what you mean by the above? Hash > >value... Prime number, how are they created & used? > > >Thanks again, > > >Steve > > Steve, > > Well like I said there are many different ways you > can achieve this and I > hesitate to suggest a way to do this because this > list doesn't let one get > away with anything. So let me emphasise that this is > *one* way you *could* > do this. > > You need a constant, fairly random identifier > associated with your client. > You might have a userid + department id or whatever. > Let's say we use the > clients machine hostname. > > Now add up the numeric characters in the name. ie. > in C this could be > > char * p = HostName; /* null terminated hostname > */ > int Key = 0; > > while (*p) Key += *p++; > > > Now we have the ASCII total for the characters we > then need to convert this > into one of 10 names. Well it's a lot easier to > convert to prime numbers so > let's convert it to one of 11 names (closest prime). > > int Hash = Key % 11; > > The '%' operator gives us the modulus ie. what's > left over after division, > the remainder. > > So now we have a number, Hash, between 0 and 10 that > is fairly evenly > spread across our clients. > We can then define 11 queues, ie. REPLYQ_0, > REPLYQ_1, > REPLYQ_2......REPLYQ_10 and use the Hash number as > part of the queue name > we open. > > Does this make it any clearer ? > > Cheers, > P. > > Paul G Clarke > WebSphere MQ Development > IBM Hursley > > Instructions for managing your mailing list > subscription are provided in > the Listserv General Users Guide available at > http://www.lsoft.com > Archive: http://vm.akh-wien.ac.at/MQSeries.archive
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