Thanks for the reply Bill, however this did not solve the problem. I
still receive the same error with your method as well.
1064: You have an error in your SQL syntax near ';
CREATE TABLE Departments (
DeptID int(10) unsigned NOT NULL auto_increment,' at line 4
> Are you first creating a new database first with mysql_create_db()
> before trying to run your schema? What error message do you get? The
> code you've posted is only creating a table.
Yes. I am:
$V2DB = "V2_SL".$CompanyID;
$result = mysql_create_db($V2DB, $linkI);
mysql_select_db ($V2DB, $linkI) or die ("Could not select ".$V2DB."
Database");
> Also, rather than opening and reading in an external file or
> doing all
> those $sql .= lines, you might have an easier time using
> heredoc syntax,
> which would let you do something like
>
> $sql = <<<SQL
> CREATE TABLE IP_Dept (
> IP_Addr int(10) unsigned NOT NULL default
> DeptID int(10) unsigned NOT NULL default
>
> ...etc
>
> SQL;
>
> $result = mysql_query($sql,$linkI);
Thanks for that tip, however it fails the same as opening the file and
same as "$sql .="
> (hopefully $linkI is your mysql connection) This way you
> don't have to bother with all that quoting.
Yes, $linkI is my connection identifier.
I just have an awful feeling that PHP/mySQL won't let me stack commands
like that because if I just do one table, like this:
$sql = <<<SQL
CREATE TABLE Schedule (
ScheduleID int(10) unsigned NOT NULL auto_increment,
TargetRange char(255) default NULL,
ScannerID int(10) unsigned NOT NULL default '0',
RunEvery char(50) default NULL,
NextRun datetime default NULL,
LastRun datetime default NULL,
PRIMARY KEY (ScheduleID)
) TYPE=MyISAM;
SQL;
It "works". However I'm dreading doing this one table at a time. Grr.
> Daevid Vincent wrote:
> > I need to use PHP to duplicate the schema of a mysql database. This
> > seems like it should be a simple task -- taking a 'template' db and
> > cloning it with a new name.
> >
> > I've tried things like:
> >
> > $filename = "myDB.sql";
> > $fd = fopen ($filename, "r");
> > $sql = fread ($fd, filesize ($filename));
> > fclose ($fd);
> >
> > And
> >
> > $lines = file($filename);
> > foreach ($lines as $line_num => $line) { $sql .= $line;
> > }
> >
> > And
> > $sql .= "CREATE TABLE IP_Dept (";
> > $sql .= " IP_Addr int(10) unsigned NOT NULL default
> > '0',";
> > $sql .= " DeptID int(10) unsigned NOT NULL default
> > '0'";
> > $sql .= ");";
> >
> > $sql .= "CREATE TABLE ResolveTable (";
> > $sql .= " IP_Addr int(10) unsigned NOT NULL default
> > '0',";
> > $sql .= " Name char(255) NOT NULL default '',";
> > $sql .= " Custom char(1) default NULL,";
> > $sql .= " Global char(1) default 'Y',";
> > $sql .= " OSVersion char(255) default NULL,";
> > $sql .= " RowID int(10) unsigned NOT NULL
> > auto_increment,";
> > $sql .= " Display enum('Yes','No') NOT NULL default
> > 'Yes',";
> > $sql .= " PRIMARY KEY (RowID)";
> > $sql .= ");";
> >
> > echo "<PRE>".$sql."</PRE><P>";
> > $result = mysql_query($sql,$linkI);
> >
> > But ALL of them fail! Ugh!!! Can I not stack commands like that? Is
> > there some way to read in a .sql file via PHP? The problem
> is that my
> > web pages are on a web server and the db is on a mysql
> server which are
> > different machines, so calling a system() or other execute style
> > function won't work for me.
> >
> > I figured, "Ah! Why don't I just make a template db on the
> server and
> > issue some SQL command to 'clone' that and rename it".
> You'd think that
> > was pretty straight forward, but I can't find any examples
> or commands
> > to do this seemingly trivial task. Ideas?
> >
> >
> >
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