Seems to me there should be a built in SQL command to duplicate a
database. Jeepers. Or to read in a .sql file from PHP and create a
database out of it (which was the original intent).
Anyways, here's a 'hack'. I'd still love to hear anyone else's more
elegant solution.
$V2DB = "V2_SL".$CompanyID;
$result = mysql_create_db($V2DB, $linkI);
if (!$result) $errorstring .= "Error creating ".$V2DB."
database<BR>\n".mysql_errno($linkI).": ".mysql_error($linkI)."<BR>\n";
mysql_select_db ($V2DB, $linkI) or die ("Could not select ".$V2DB."
Database");
/*
//TODO: None of these below here work. Ugh! so frustrating!!
//$filename = "/mypath/todb/V2_DB.sql";
//$fd = fopen ($filename, "r");
//$sql = fread ($fd, filesize ($filename));
//fclose ($fd);
//$lines = file($filename);
//foreach ($lines as $line_num => $line) { $sql .= $line; }
//$sqlTables = explode(";",$sql);
//foreach ($sqlTables as $table)
//{
// echo "<PRE>$table</PRE><p><hr>\n";
// $result = mysql_query($sql,$linkI);
// if (!$result) $errorstring .= "Error creating ".$V2DB."
".$table." table<BR>\n".mysql_errno($linkI).":
".mysql_error($linkI)."<BR>\n";
//}
*/
//You must have already created the "V2_Template" database.
//This will make a clone of it, including data.
$tableResult = mysql_list_tables ("V2_Template");
while ($row = mysql_fetch_row($tableResult))
{
$tsql = "CREATE TABLE ".$V2DB.".".$row[0]." AS SELECT * FROM
V2_Template.".$row[0];
echo $tsql."<BR>\n";
$tresult = mysql_query($tsql,$linkI);
if (!$tresult) $errorstring .= "Error creating
".$V2DB.".".$row[0]." table<BR>\n".mysql_errno($linkI).":
".mysql_error($linkI)."<BR>\n";
}
> -----Original Message-----
> From: Daevid Vincent [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, December 17, 2002 1:16 AM
> To: [EMAIL PROTECTED]
> Cc: 'Bill Lovett'
> Subject: RE: How can I duplicate a mysql template database?
>
>
> Thanks for the reply Bill, however this did not solve the problem. I
> still receive the same error with your method as well.
>
> 1064: You have an error in your SQL syntax near ';
> CREATE TABLE Departments (
> DeptID int(10) unsigned NOT NULL auto_increment,' at line 4
>
> > Are you first creating a new database first with mysql_create_db()
> > before trying to run your schema? What error message do you
> get? The
> > code you've posted is only creating a table.
>
> Yes. I am:
>
> $V2DB = "V2_SL".$CompanyID;
> $result = mysql_create_db($V2DB, $linkI);
> mysql_select_db ($V2DB, $linkI) or die ("Could not select ".$V2DB."
> Database");
>
> > Also, rather than opening and reading in an external file or
> > doing all
> > those $sql .= lines, you might have an easier time using
> > heredoc syntax,
> > which would let you do something like
> >
> > $sql = <<<SQL
> > CREATE TABLE IP_Dept (
> > IP_Addr int(10) unsigned NOT NULL default
> > DeptID int(10) unsigned NOT NULL default
> >
> > ...etc
> >
> > SQL;
> >
> > $result = mysql_query($sql,$linkI);
>
> Thanks for that tip, however it fails the same as opening the file and
> same as "$sql .="
>
> > (hopefully $linkI is your mysql connection) This way you
> > don't have to bother with all that quoting.
>
> Yes, $linkI is my connection identifier.
>
> I just have an awful feeling that PHP/mySQL won't let me
> stack commands
> like that because if I just do one table, like this:
>
> $sql = <<<SQL
> CREATE TABLE Schedule (
> ScheduleID int(10) unsigned NOT NULL auto_increment,
> TargetRange char(255) default NULL,
> ScannerID int(10) unsigned NOT NULL default '0',
> RunEvery char(50) default NULL,
> NextRun datetime default NULL,
> LastRun datetime default NULL,
> PRIMARY KEY (ScheduleID)
> ) TYPE=MyISAM;
> SQL;
>
> It "works". However I'm dreading doing this one table at a time. Grr.
>
> > Daevid Vincent wrote:
> > > I need to use PHP to duplicate the schema of a mysql
> database. This
> > > seems like it should be a simple task -- taking a
> 'template' db and
> > > cloning it with a new name.
> > >
> > > I've tried things like:
> > >
> > > $filename = "myDB.sql";
> > > $fd = fopen ($filename, "r");
> > > $sql = fread ($fd, filesize ($filename));
> > > fclose ($fd);
> > >
> > > And
> > >
> > > $lines = file($filename);
> > > foreach ($lines as $line_num => $line) { $sql .= $line;
> > > }
> > >
> > > And
> > > $sql .= "CREATE TABLE IP_Dept (";
> > > $sql .= " IP_Addr int(10) unsigned NOT NULL default
> > > '0',";
> > > $sql .= " DeptID int(10) unsigned NOT NULL default
> > > '0'";
> > > $sql .= ");";
> > >
> > > $sql .= "CREATE TABLE ResolveTable (";
> > > $sql .= " IP_Addr int(10) unsigned NOT NULL default
> > > '0',";
> > > $sql .= " Name char(255) NOT NULL default '',";
> > > $sql .= " Custom char(1) default NULL,";
> > > $sql .= " Global char(1) default 'Y',";
> > > $sql .= " OSVersion char(255) default NULL,";
> > > $sql .= " RowID int(10) unsigned NOT NULL
> > > auto_increment,";
> > > $sql .= " Display enum('Yes','No') NOT NULL default
> > > 'Yes',";
> > > $sql .= " PRIMARY KEY (RowID)";
> > > $sql .= ");";
> > >
> > > echo "<PRE>".$sql."</PRE><P>";
> > > $result = mysql_query($sql,$linkI);
> > >
> > > But ALL of them fail! Ugh!!! Can I not stack commands
> like that? Is
> > > there some way to read in a .sql file via PHP? The problem
> > is that my
> > > web pages are on a web server and the db is on a mysql
> > server which are
> > > different machines, so calling a system() or other execute style
> > > function won't work for me.
> > >
> > > I figured, "Ah! Why don't I just make a template db on the
> > server and
> > > issue some SQL command to 'clone' that and rename it".
> > You'd think that
> > > was pretty straight forward, but I can't find any examples
> > or commands
> > > to do this seemingly trivial task. Ideas?
> > >
> > >
> > >
> >
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