I have a link to a file in the servlet, something like "https://myserver.com/special-directory/file.zip";
If I create the directory as follows: /export/home/tomcat/webapps/ROOT/special-directory/ and put "file.zip" in that directory, it all works perfectly.
HOWEVER, if instead of creating the actual directory, I create a symbolic link to a different directory
(i.e. in ROOT I type "ln -s /export/home/myfiles/directory special-directory", the linked directory appears, and (in unix) I can see/access the files. BUT - tomcat no longer finds the files, even though the linked directory has the required name and files.
Is there some way to make tomcat "see" a linked directory?
The problem is that the servlets are writing a data file for offline use in one directory, and then I was hoping to symbolically link that directory under ROOT so the user could access it. Worst case, I guess I could write to "ROOT/special-directory", but I didn't really want the user files stored there - just a link. Since these files are created "on the fly", a hard link won't work.
Thanks very much in advance,
-Richard
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