IN-14 strike at 170V, but when multiplexed this should be a bit
higher. That's why it's set to 200 volts. It then drops to 140V
according to the datasheet, but in reality, I measured 144. So if I
take 200-140 it's 60 volts across the anode resistor, giving the peak
of 8mA.
But to be honest, I am really confused with this. By my calculations,
with 26.7% duty cycle per tube, for current of 2mA, I should have a
peak of 3.864mA ( 2/sqrt(0.267) = 3.864).
So with my supply stable at 200V and anode resistors of 7.5K, I should
get the 8mA peak on one tube, or 16mA on two tubes, but I really
measure current of 6.4mA alltogether that goes from my supply. How is
this possible? Why should my supply give me 48mA when I need only
6.5mA for two tubes at a time? By the way, I am using blanking period
of 200us, so maybe the current really settles by this time, so the
supply needs to give enough current for only 2 tubes.
Can someone clear this out to me?

And about that spider web.. it isn't really as messy as it looks in
the video. It's just a matter of viewing angle. And everything is
organised by cable color.

Thanks

On Mar 14, 1:24 am, Cobra007 <mic...@xiac.com> wrote:
> Wow, I like that spider web you created there!
>
> How exactly did you estimate that a 7.5k resistor would result in a
> 8mA tube current? Honestly, I do not know the nominal voltage of the
> tube but I don't think it will be less than 150V. In that case, you
> have a maximum of 50V across your resistor which would only be 6.7mA.
> If you measure 5.5mA, the voltage across the resistor would be 41.25V
> so in that case, your resistor should have been between 4.7k and 5.2k
> to come to 8mA. My best guess is 4.7k. Try one tube and see if the
> value is then closer to 8mA for that tube. Also check that your 200V
> stays stable and can supply the required 48mA.
>
> Michel
>
> On Mar 14, 10:56 am, Imbanon <imba.a...@gmail.com> wrote:
>
>
>
>
>
>
>
> > Got my hands on some older Tektronix oscilloscope and a Fluke 199c. I
> > did quite a lot of measurements, even with the current probe. I
> > learned a lot about the tubes and their behaviour, but didn't really
> > solve my problem.
> > I ended up calculating my anode resistors (around 7.5k), that should
> > give a peak of 8mA, but gives 5.5mA measured with a scope. You can see
> > the result in the video below. The quality isn't at it's finest, but
> > it's better than nothing!
> > Check it out and tell me what you think.
> > Also, the supply is set to 200V. It that too 
> > much?http://youtu.be/p7QNEL8s4l4
>
> > Thanks everyone
>
> > On Mar 6, 10:10 pm, "Frank Bemelman" <bemel...@franktechniek.nl>
> > wrote:
>
> > > AC DMM’s always excluded the DC component, if I am not mistaken. For a
> > > mainly
> > > troubleshooting tool (citation needed), that is not a bad choice. After 
> > > all,
> > > many AC signals
> > > found in circuits have a DC offset. Assuming sinewaves makes the design of
> > > the meter
> > > easier (cheaper).
>
> > > I would not expect a different behaviour from a DMM that is TRUE RMS. Nice
> > > to have
> > > that AC/DC switch though, on the Tek meters. But I’m still a Fluke only 
> > > guy
> > > ;-)
>
> > > Frank
>
> > > From: Nick
> > > Sent: Tuesday, March 06, 2012 4:03 PM
> > > To: neonixie-l@googlegroups.com
> > > Subject: [neonixie-l] Re: Calculating multiplexed nixie's RMS current
>
> > > Yes, RMS has only one physical definition, but in the case of DMMs the
> > > actual implementation is obfuscated.
>
> > > "true" RMS in a DMM context is an RMS calculation that does not assume a
> > > sine wave - most cheaper DMMs do indeed assume a sine wave input.
>
> > > Then there are "true RMS" (and indeed "ordinary" RMS) DMMs that may or may
> > > not include any DC component, or at least in the Tek case, give you the
> > > choice.
>
> > > Old meters indeed did use to measure the heat produced in a resistor - the
> > > definition of the "RMS value" used was that of the DC voltage that would
> > > give the equivalent heating effect to the signal under inspection.
>
> > > Nick
>
> > > On Tuesday, March 6, 2012 2:16:45 PM UTC, GastonP wrote: Actually there is
>
> > > only a definition of RMS, not subject to
> > > "trueness" :)
>
> > >http://en.wikipedia.org/wiki/Root_mean_square
>
> > > AFAIK, the old instruments that gave a true-"true RMS" output measured
> > > the heat generated by the signal when applied to a resistor. That way
> > > the waveform shape did not affect the measurement, and they were able
> > > to measure with the DC component included, something fake-"True RMS"
> > > instruments can't do.
> > > Many of the existing instruments assume sinusoidal signals and thus
> > > are subject to gross errors.
>
> > > Gaston
>
> > > On Mar 5, 6:15 am, Nick <n...@desmith.net> wrote:> On Monday, March 5, 
> > > 2012 8:46:42 AM UTC, Cobra007 wrote:
>
> > > > > Yes, you're right Nick, the Fluke is indeed AC coupled. I didn't
> > > > > expect that to be honest as it undermines the definition of "true RMS"
> > > > > but a simple battery test shows 0V RMS :-).
>
> > > > Its not a commonly known problem, even among professional EEs. One of my
> > > > DMMs, a Tektronix DMM916, has the option to include/exclude any DC
> > > > component as required. I've had "forthright" discussions with some over
> > > > what theoretically constitutes true-RMS vs. what they expect/want in
> > > > actuality.
>
> > > > Nick
>
> > > --
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> > > To view this discussion on the web, 
> > > visithttps://groups.google.com/d/msg/neonixie-l/-/cOKZXWW5GXwJ.
> > > To post to this group, send an email to neonixie-l@googlegroups.com.
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