I can smell a misunderstanding here (from my side, that is). What are you trying to achieve? I just read your previous posts, it seems like you're after 2mA average current per tube, so your power supply should be able to deliver 12mA in total.
I assume the anodes from the 2 tubes go through 1 resistor to the 200V supply (2 anodes share 1 resistor). The peak current for 2 tubes should be 6mA * (33.3 / 26.7) = 7.5mA With 60V across the resistor, you would then need 8k resistors. However, it is probably a bit less, maybe more like 6.8k as the voltage is probably less than 60V. I really liked the spiderweb, that was not a joke, I think it looks good. Michel -- You received this message because you are subscribed to the Google Groups "neonixie-l" group. To post to this group, send an email to neonixie-l@googlegroups.com. To unsubscribe from this group, send email to neonixie-l+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/neonixie-l?hl=en-GB.
