No embedded image...

On Tue, May 17, 2016 at 4:40 AM, Joe Croft <cro...@gmail.com> wrote:

> Hi Jon,
>
> I have embedded the picture below. It's a good guess if you post the
> circuit on a forum, you don't mind others re-posting it. I am definitely
> using in IN-13. 3 legs vs 2, it's hard to miss the 3rd leg ;).
>
> Gregebert,
>
> Sadly, for the 'art' of the clock, it has to be an IN-13 if for no other
> reason, to keep the size of the board in check, not to mention the drivers!
>
> -joe
>
> On Tue, May 17, 2016 at 1:52 AM, Jon <dekat...@nomotron.com> wrote:
>
>>
>> I don't see a circuit in the link - it links on to a dead site. Can you
>> post here? Some thoughts...
>>
>> Are you sure you are using IN-13 not IN-9 ? 13mA to fully light the tube
>> is around what might be expected for a slightly cathode poisoned IN-9. It's
>> easy to check even if the tube markings have worn off: IN-13 has three
>> terminals, IN-9 has two.
>>
>> I would expect both tube types to require about 150V to strike reliably,
>> and then the voltage across the tube will drop down to the maintenance or
>> running voltage in the 95V - 105V range. Were you anticipating something
>> different?
>>
>> Jon
>>
>>
>>
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