+ 1.84375 0 2 cbr 210 ------- 0 0.0 3.1 225 610 - 1.84375 0 2 cbr 210 ------- 0 0.0 3.1 225 610 r 1.84471 2 1 cbr 210 ------- 1 3.0 1.0 195 600 r 1.84566 2 0 ack 40 ------- 2 3.2 0.1 82 602 + 1.84566 0 2 tcp 1000 ------- 2 0.1 3.2 102 611 - 1.84566 0 2 tcp 1000 ------- 2 0.1 3.2 102 611 r 1.84609 0 2 cbr 210 ------- 0 0.0 3.1 225 610 + 1.84609 2 3 cbr 210 ------- 0 0.0 3.1 225 610 d 1.84609 2 3 cbr 210 ------- 0 0.0 3.1 225 610 - 1.8461 2 3 cbr 210 ------- 0 0.0 3.1 192 511
1st line 610 packet did enque and then deque, but look at 3rd and 4th filed. you'll notice that the packet is from 0 node to 2node . when the packet arrived at 2node, according to its routing, the sorce and destination node became 2node and 3node. this is how you know the routing the packet is using. wish you good luck . CaiJie
