On Tue, Jun 02, 2009 at 03:49:13PM +0200, Steffen DETTMER wrote: > (OT) > > * Michael S. Zick wrote on Sun, May 31, 2009 at 08:05 -0500: > > A more general solution would be: > > > > # Am I running as user 0 (root)? > > uid=$(/usr/bin/id -u) 2>/dev/null > > if [ $uid == 0 ] ; then > > BTW, shouldn't it be just one "=" (to be compliant with POSIX and > /usr/bin/test)?
Yes, and quotes are required, just in case "id -u" fails, and the "uid" value is empty: if [ "$uid" = 0 ] Michael must have had [[ ]] in mind, but forgot the outer "[]". [[ $uid == 0 ]] note, the "==" is actually a pattern match when the second operand is not quoted. $ [[ foo == f* ]] && echo match || echo no match match $ [[ foo == "f*" ]] && echo match || echo no match no match For numeric equality: [[ $uid -eq 0 ]] but, when comparing with 0, this returns true also when $uid is not a number. -- Viktor. ______________________________________________________________________ OpenSSL Project http://www.openssl.org User Support Mailing List openssl-users@openssl.org Automated List Manager majord...@openssl.org