Think of the lenses as simple, one element lenses. Think of the center of the lenses as fulcrums (pivot points) of a "light lever" too. If the eyepiece has a short focal length, the distance from the image in the telescope to the lens "fulcrum" is short. The distance from the lens "fulcrum" to your retina is longer. Small image in the tube, big image on your retina. Shorter focal length on the lens even larger image on your retina.

Yes, I know there is another lens involved, your eye's lens, but this is sufficient to demonstrate the principle.

Regards,
Bob...

From: "Tom C" <[EMAIL PROTECTED]>


Bob wrote:


Think of it like a lever. The objective is focusing the image in the air inside the telescope's tube. The longer the focal length, the larger this image (like a camera lens). The eyepiece is used like a magnifying glass to view this image "in the ether". The shorter the focal length of the magnifying glass, the larger the image to your eye.



There's something fundamental I'm missing, maybe you can help. I've been wrestling with the idea for a while... why, on let's say a camera lens or optical tube, does longer focal length = larger image, and on an eyepiece longer focal length = smaller image (less magnification). In my mind, it seems that an eyepiece is a lens with an optical tube and therefore it should work reverse of what you've stated regardless of whether it's focusing on he object itself or an image of the object "in the ether".


I realize your statement is quite correct. What am I not getting? I'm sure I need to dig out a basic optics book.




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