demerphq wrote:
I wasn't suggesting that this should fail and wouldnt suggest it should either.I was suggesting that my $a=[]; is_deeply([$a,$a],[[],[]])
So doesn't that just come down to is_deeply([], []) failing? Can we really say that x=y; but x,x != y,y? If that is the case, the it is completely non-intuitive. -- Michael Peters Developer Plus Three, LP
